Area is length times width. so 3.5 * 3 would be an area of 10 and a half
Answer:
2|6 i think
Step-by-step explanation:
Answer:
a= infinite
b= one sol
c= no solutions
d= infinite
Step-by-step explanation:
I how this helped. Basically solve for X and see if you can. If you can't it is zero solutions, if you can solve it one way then it is one solution, and if will will always solve then it is infinite solutions.
Answer:
Pounds for cashew- 20.96
Pounds for Brazilian nut- 11.04
Step-by-step explanation:
Let c be the pounds of cashew
Let b ne the pound of Brazilian but
32×6.24
= 199.68
7.1c + 4.60b= 199.68.......equation 1
c + b= 32..........equation 2
From equation 2
c= 32-b
Sub 32-b for c in equation 1
7.1(32-b) + 4.60b= 199.68
227.3-7.1b+4.60b, = 199.68
227.3-2.5b= 199.68
-2.5b= 199.69-227.3
- 2.5b= -27.61
b= 27.61/2.5
b= 11.04
Sub 11.04 for b in equation 2
c+b= 32
c + 11.04= 32
c= 32-11.04
c= 20.96
Answer:
NO.
Step-by-step explanation:
The Professor's hypothesis:
An introductory course in Logic will affect college students with their other studies (will affect their Great Point Average - GPA).
25 students are used as the experimental group while the rest of the class are the control group.
The mean GPA in a sample size (SS) of 6 is = 2.58
The mean GPA in the full sample size of 25 would be = 10.75 by crossmultiplying.
This makes me believe the question was written wrongly. I assume SD (standard deviation) of 0.6 instead of SS (sample size) of 6.
Going by this, if standard deviation is 0.6 then the interval within which the GPA of the experimental group (the 25 students) falls is:
[2.58 - 0.6] to [2.58 + 0.6]
= 1.98 to 3.18
The rest of the graduating class (the control group) had a mean GPA of 2.33
Can the professor conclude that the GPA for the sample is significantly different from that of the control group?
The answer is NO because the GPA of the control group falls within the GPA interval of the experimental group!