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2 years ago

Each lap around the track is 400 meters. How many meters does someone run if they run 2 laps?

Mathematics

2 answers:

almond37 [142]2 years ago

8 0

Answer : 800 meters

Explanation :
1 lap = 400 meters

2laps = ?

1x2=2
400x2=800

Mark Brainliest

Katena32 [7]2 years ago

7 0

Answer:800 meters

Step-by-step explanation:

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Diano4ka-milaya [45]

The first thing you should do for this case is to take 35% out of 9.95
We have then
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Then, we must add this value from the original price of a dozen
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3 years ago

5. The length of a rectangular swimming pool is 50 yards, and the width of the pool is 16

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The answer is C. I got this by doing a^2 + b^2= c^2. 50^2 + 16^2=c^2, 2500 + 256 = c^2, 2756 = c^2, then you take the square root of 2756 and that gives you your answer 52.50 yards. Hope this helps :D

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2 years ago

4x + 5x + 12 = 6(x-2) Math

Rashid [163]

Hi there! :)

$\large\boxed{x = -8}$

4x + 5x + 12 = 6(x - 2)

Combine like terms and distribute the coefficient outside of the parenthesis:

9x + 12 = 6(x) + 6(-2)

9x + 12 = 6x - 12

Subtract 6x from both sides:

9x - 6x + 12 = 6x - 6x - 12

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3 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

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ahrayia [7]

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3 years ago