1st let's calculate the decreasing rate & let V₁ be the initial value & V₂ the final's
we know that V₂=V₁.e^(r,t) where r=rate & t-time (& e=2.718)
After t= 2 years we can write the following formula
2350,000=240,000.e^(2r)==> 235,000/240000 = e^(2r) =>47/48=e^(2r)
ln(47/48)=2rlne==> ln(47/48)=2rlne=2r (since lne =1)
r= ln(47/48)/2==>r=-0.0210534/2 =-0.01052 ==> (r=-0.01052)
1) Determine when the value of the home will be 90% of its original value.
90% of 240000 =216,000
Now let's apply the formula
216,000=240,000,e^(-0.01052t), the unknown is t. Solving it by logarithm it will give t=10 years
1.a) Would the equation be set up like so: V=240e^.09t? NON, in any case if you solve it will find t=1 year
2)Determine the rate at which the value of the home is decreasing one year after : Already calculated above :(r=-0.01052)
3)The relative rate of change : it's r = -0.01052
When it comes to sampling methods, random sampling is one of the most effective. The principal wants the results of his or her sample to be as fair as possible, so it is best to choose students randomly, and in a neutral environment. The mall is not a neutral environment because not all students have access to the mall, and even those who do are not guaranteed to provide accurate results. The same goes for a basketball game, and student council. Samples taken from these environments are likely to produce more bias. However, collecting a survey from every tenth student entering the school one morning is more likely to produce accurate results that are representative of the school population.
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10
Step-by-step explanation:
replace p with 5
2×5= 10
Please, proofread your problem statements before posting them. Your "If 1,600 people live 25% of the population how many people need to leave" should be written as "<span>If the whole population is 1,600 and 25% of them need to leave, how many must leave?"
0.25(1600) = 400
400 people need to leave. This is 25% of the entire population, or 25% of 1600 people. Please note: it's "leave," not "live."</span>