17x-2 just add the two functions
It is unchanged because the same number would still be in the middle and there would still be the same amount of numbers
if
11,15,21,22,23,27,30 before 22 is the median
if
11,15,21,22,23,27,30 after 22 is still the median
The median is unchanged
Sent a picture of the solution to the problem (s). Proportions are a quick set up to find a part of two things being compared. You will use this method a lot in math and science.
Answer:
6
Step-by-step explanation:
1/6 of 36 is 6
2/3 of 36 is 24
6+24=30
36-30=6
<3
d<em>y</em>/d<em>x</em> = 4 + √(<em>y</em> - 4<em>x</em> + 6)
Make a substitution of <em>v(x)</em> = <em>y(x)</em> - 4<em>x</em> + 6, so that d<em>v</em>/d<em>x</em> = d<em>y</em>/d<em>x</em> - 4. Then the DE becomes
d<em>v</em>/d<em>x</em> + 4 = 4 + √<em>v</em>
d<em>v</em>/d<em>x</em> = √<em>v</em>
which is separable as
d<em>v</em>/√<em>v</em> = d<em>x</em>
Integrating both sides gives
2√<em>v</em> = <em>x</em> + <em>C</em>
Get the solution back in terms of <em>y</em> :
2√(<em>y</em> - 4<em>x</em> + 6) = <em>x</em> + <em>C</em>
You can go on to solve for <em>y</em> explicitly if you want.
√(<em>y</em> - 4<em>x</em> + 6) = <em>x</em>/2 + <em>C</em>
<em>y</em> - 4<em>x</em> + 6 = (<em>x</em>/2 + <em>C </em>)²
<em>y</em> = 4<em>x</em> - 6 + (<em>x</em>/2 + <em>C </em>)²
