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balu736 [363]
2 years ago
7

What is the volume of the rectangular prism

Mathematics
2 answers:
scoundrel [369]2 years ago
7 0

270 in3 the Three is for volume.

MakcuM [25]2 years ago
3 0

Answer:

6(9)(5)=270 in3

Step-by-step explanation:

length x width x height

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A map has a scale of 1 cm to 16 km.
ra1l [238]
1cm = 16km

1cm • x = 23.1cm
x = 23.1

16km • 23.1 = 369.6km

The real distance is 369.6km.
4 0
3 years ago
Given triangle TVU list the sides of the shortest to longest
Margaret [11]

Answer:

VU, VT, TU

Step-by-step explanation:

List the side lengths of triangle TUV from shortest to longest.

A. VU, VT, TU

B. VT, TU, VU

C. VT, VU, TU

D. VU, TU, VT"

8 0
2 years ago
Which statement about 307° is correct?
77julia77 [94]

Answer:

a hope help you stay happy and safe

4 0
3 years ago
Read 2 more answers
(3 points) Blades of grass Suppose that the heights of blades of grass are Normally distributed and independent, with each heigh
NemiM [27]

The final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

What is the normal distribution?

A continuous probability distribution for a real-valued random variable in statistics is known as a normal distribution or Gaussian distribution.

If x follows a normal distribution with mean μ and standard deviation σ then the distribution of

\sum_{i =1}^{n}x_{i}  follows an approximately normal distribution with a mean n\mu and standard deviation \sqrt{n }\sigma

let x be the height of blades of grass

x follows normal distribution with mean = μ = 4 and standard deviation = σ = 0.75.

Y = x1 + x2 +...........+x10

Y = \sum_{i =1}^{10}x_{i}

Distribution of Y is normal with,

Mean = \mu _{y}=10*4 = 40 and standard deviation = \sigma _{y}=\sqrt{10}*0.75 = 2.3717

a)

P( Y < 42.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

=NORMDIST( x, mean, SD , 1 )      

=NORMDIST(42.5, 40, 2.3717, 1 )

=0.8541

P( Y < 42.5 )  = 0.8541

b)

P( 39.5 < Y < 40.5 ) = P( Y < 40.5 ) - P( Y < 39.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

P( Y < 40.5 )  =NORMDIST(40.5, 40, 2.3717, 1 ) = 0.5835

P( Y < 39.5 ) = NORMDIST(39.5, 40, 2.3717, 1 ) = 0.4165

P( 39.5 < Y < 40.5 ) = 0.5835 - 0.4165  = 0.1670

P( 39.5 < Y < 40.5 ) = 0.1670

Hence, the final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

To learn more about the normal distribution visit,

brainly.com/question/4079902

#SPJ4

5 0
1 year ago
I need help pls this is really hard
Greeley [361]

Answer:

I cant see it wrong angle lol

8 0
3 years ago
Read 2 more answers
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