Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
Answer:
3(x−4)(x+2)
Step-by-step explanation:
Answer:
9
Step-by-step explanation:
Y ~ X
Y = KX
K = Y/X
K = 36/4
K = 9
Answer:
(-5/7)^17
Step-by-step explanation:
When multiplying numbers to a certain power, you will add the powers together. When dividing numbers to a certain power, you will subtract the powers.
