(1/2)[logb(b^2)+logb(8x)]
=(1/2)[2+logb(8x)]
=1+(1/2)logb(8x)
hope this helps you
Answer: option b.
Step-by-step explanation:
To solve this exercise you must keep on mind the identities shown below:
1)
2)
3)
Therefore, to rewrite you must substitute identities and simplify the expression, as following:
Therefore, as you can see, the answer is the option b.
Answer:
A.)
In 2 months, Rex is 6 pounds and in 8 months he's 9lbs (from 2 to 8 is 6 months). So I inferred that to get to 9lbs from 6lbs is to go 0.5 pounds more each month.
B.)
2 = 6
3 = 6.5
4 = 7
5 = 7.5
6 = 8
7 = 8.5
8 = 9
C.) I don't think I can create a linear model here. So I don't think its nessesary.
D.)
If Rex were to grow over the expected 6 months, it would be 45.
The distance between point A and point B is 10.