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nalin [4]
2 years ago
15

Help me with khan geometry. (Explain or give answer no link to answer thx)

Mathematics
1 answer:
NikAS [45]2 years ago
7 0

Answer:

\boxed{\sf 200\pi}

Step-by-step explanation:

We know that the volume of a cone:-

\boxed{\sf  \pi r^2\cfrac{h}{3}}

(r = 10) (h = 6)

\sf \pi \times 10^2\times\cfrac{6}{3}

<u>Divide numbers:-</u>

\sf \cfrac{6}{3}=\boxed{2}

\sf 10^2\times \:2\pi

\sf 100\times \:2\pi

<u>Multiply numbers:-</u>

\boxed{\sf 200\pi}

Therefore, your answer is 200π³

We could also multiply 200 by 3.14 which will give you 628 units³.

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Answer:

y=\frac{4}{5}x+4

Step-by-step explanation:

You'll need to get this equation in slope-intercept form by solving for y. I do a little extra here to get it in the correct form, but I think it's pretty clear. Let me know if I need to clarify.

\\\\\frac{8x}{5}-2y=-8\\\\-2y=-\frac{8x}{5}-8\\\\2y=\frac{8x}{5}+8\\\\y=\frac{4}{5}x+4

Once it's in slope-intercept form, both the slope and the y-intercept are readily available so you can easily graph it. I graphed both of them in the attached image so you can see that they are the same line.

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Step-by-step explanation:

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Find the area of a triangle with a =33, b =51, and c =42.
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Answer:

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Step-by-step explanation:

1. You can use the Heron's formula to calculate the area of the triangle, which is:

K=\sqrt{s(s-a)(s-b)(s-c)}

Where:

s=\frac{a+b+c}{2}

2. Calculate s:

s=\frac{33+51+42}{2}\\s=63

3. Substitute values into the formula shown above and calculate the area, as following:

K=\sqrt{63(63-33)(63-51)(63-42)}\\K=690.1units^{2}

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