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ikadub [295]
3 years ago
13

Imagine a pedigree that traces an inherited disorder found in individuals with two recessive alleles for gene D. The pedigree sh

ows three siblings with the genotypes DD, Dd, and dd. Did the parents of these three children have the disorder? Explain.
Biology
1 answer:
d1i1m1o1n [39]3 years ago
5 0
No, the parents don't have a disorder, but they carry recessive allele.

Individuals with the disorder are recessive homozygous (dd). It is known that recessive allele produces its phenotype only when it is paired with another recessive allele. Thus, to have offspring with disorder (with genotype dd), parents must be heterozygous, or one parent is recessive homozygous, and the other one is heterozygous. 

Now, let's imagine both situations:

Parents:            Dd           x              dd
Offspring:       Dd       Dd         dd           dd

In this cross, there is no possibility to have children with genotype DD.

Parents:            Dd           x              Dd
<span>Offspring:       DD       Dd         Dd           dd
</span>
In this cross all three genotypes DD, Dd, or dd could be inherited.

It can be concluded that three children with <span>the genotypes DD, Dd, and dd, the parents must be heterozygous which do not have the disorder.</span>
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8 0
4 years ago
A geologist is studying two different rhyolite flows to determine if they were erupted at the same time.
ss7ja [257]
Q1. The answer is 1.

It can be calculated using the equation:

 (1/2)ⁿ = x

x - decimal amount remaining, 

n - a number of half-lives.


x = 50% = 50/100 = 0.5

n = ?

(1/2)ⁿ = 0.5

log((1/2)ⁿ) = log(0.5)

n * log(1/2) = log(0.5)

n * log(0.5) = log(0.5)

n = log(0.5)/log(0.5)

n = 1


Q10. The answer is 2.


It can be calculated using the equation:

 (1/2)ⁿ = x

x - decimal amount remaining, 

n - a number of half-lives.


Rhyolite #2 has 25% of the parent H remaining:

x = 25% = 25/100 = 0.25

n = ?

(1/2)ⁿ = 0.25

log((1/2)ⁿ) = log(0.25)

n * log(1/2) = log(0.25)

n * log(0.5) = log(0.25)

n = log(0.25)/log(0.5)

n = -0.602 / - 0.301

n = 2



Q3. The answer is 100 million years.


A number of half-lives (n) is a quotient of total time elapsed (t) and length of half-life (H):

n = t/H

n = 1

t = ?

H = 100 000 000 years


n = t/H

t = n * H

t = 1 * 100 000 000 years

t = 100 000 000 years<span>

</span>

4 0
4 years ago
•. otal genomic structure of an organism inherited from parents is known as -
joja [24]
I think the answer is a sorry if I get it wrong
8 0
3 years ago
Read 2 more answers
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