Computers and Technology:
1 answer:
Answer:
The algorithm:
Input days
sum = 0
for i = 1 to
input text
sum = sum + text
end for
average = sum/days
print average
The program in pascal:
var days, sum, text, i:integer;
var average : real;
Begin
write ('Days: '); readln(days);
sum:=0;
for i := 1 to do
write ('Text: '); readln(text);
sum:=sum+text;
end;
average := (sum/days);
writeln ('The average text is' , average);
End.
Explanation:
This declares all variables
var days, sum, text, i:integer;
var average : real;
This begins the program
Begin
This gets the number of days from the user
write ('Days: '); readln(days);
Initialize sum to 0
sum:=0;
This iterates through the days
for i := 1 to do begin
This gets the text for each day
write ('Text: '); readln(text);
This sums up the texts
sum:=sum+text;
End loop
end;
Calculate average
average := (sum/days);
Print average
writeln ('The average text is' , average);
End program
End.
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Answer:
The equation of the line is y = -4·x + 16
10 points on the line include;
(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)
Explanation:
The given points through which the line passes are;
(4, 0) and (3, 4)
The slope, 'm', of the line is given as follows;
Therefore, the slope of the line is (4 - 0)/(3 - 4) = -4
In point and slope form we can get;
The equation of the line in point and slope form is therefore;
y = -4·(x - 4) = -4·x + 16
The equation of the line in slope and intercept form is
y = -4·x + 16
10 points on the line are obtained using the equation of the line and the desired x-values input into cells on MS Excel and presented here as follows;
(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)
