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Lady bird [3.3K]
2 years ago
10

ANSWER FAST PLEASE WHORVER IS FIRST GETS BRAINLIEST

Mathematics
1 answer:
nata0808 [166]2 years ago
8 0

Answer:-3/5

Step-by-step explanation:

rise/run

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Lynn asked six friends how many cars their parents own. She recorded 1, 1, 2, 2, 2, and 4 cars.
Paladinen [302]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
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Una escalera se apoya en una pared con un ángulo de 40º. Si se apoyase con un ángulo de 55º, se conseguiría una altura 35 cm may
sdas [7]

Answer: L ≈ 2.0 m

Step-by-step explanation:

Lsin40 = h

Lsin55 = h + 0.35

Lsin55 = Lsin40 + 0.35

Lsin55 - Lsin40 = 0.35

L(sin55 - sin40) = 0.35

L = 0.35 / (sin55 - sin40)

L = 1.98452 ≈ 2.0 m

3 0
2 years ago
Y - x = 4<br><br><br> please help!!
UNO [17]
Add the x to both sides and it turns into Y = x + 4. If this isn't what you're looking for, please provide the answer choices.
6 0
3 years ago
5 men take 45hours to build a wall.how long will it take 9men working at the same wall?​
Karolina [17]

Answer:

<u>25 hours</u>

Step-by-step explanation:

It takes 5 men 45 hours to build a wall.

So, if no. of men increases by 1.8 [∴ 5 x 1.8 = 9],

then time taken reduces by that same amount.

=> 45 hours / 1.8

=> 45 / (9/5)

=> 45 x 5 / 9

=> 5 x 5

=> <u>25 hours</u>

7 0
2 years ago
According to the MIT Airline Data Project, American Airlines controlled 15.5% of the domestic market during a recent year. A ran
Naya [18.7K]

Answer:

0.0143

Step-by-step explanation:

In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.

We proceed as follows;

The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155

Let’s call this probability p

The probability that he/she isn’t on the flight, let’s call this q

q =1 - p= 0.845

Sample size, n = 155

P(X < A) = P(Z < (A - mean)/standard deviation)

Mean = np

= 125 x 0.155

= 19.375

Standard deviation = √npq

= √ (125 x 0.155x 0.845)

= 4.0462

P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)

= P(Z < (10.5 - 19.375)/4.0462)

= P(Z < -2.19)

= 0.0143

4 0
3 years ago
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