All categories

3 years ago

How many right angles does a trapezoid have

Mathematics

1 answer:

zysi [14]3 years ago

3 0

A maximum of 2 and a minimum of 0

You might be interested in

Whatss the Median??????????????????????///

Andrej [43]

<em>The median is the middle point in a dataset half of the data points are smaller than the median and half of the data points are larger. To find the median Arrange the data points from smallest to largest. If the number of data points is odd the median is the middle data point in the list.</em>

3 0

3 years ago

What is the fractional equivalent of 225%?

vitfil [10]

You would start out by putting 225 over 100 then simplifying from there. You would end up getting 9/4. As a mixed number that would be 2 and 1/4.

7 0

3 years ago

Read 2 more answers

Grandma baked 96 cookies and gave them to her grandchildren. One of the grandchildren, Cindy, received c fewer cookies than she

frosja888 [35]

Answer:

12-c

Step-by-step explanation:

Let c be Cindy's cookies

Solution:

Each child should have gotten 12 cookies because 96/8 is 12 but Cindy got c less so the answer would be 12-c.

6 0

3 years ago

Help me plz I'm stuck

Lelechka [254]

The answer to one would be 25534

3 0

3 years ago

A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are

Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that $p = 0.75$ , and four games means that $n = 4$

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164$

0.3164 = 31.64% probability the team wins all its conference games

4 0

3 years ago