How many right angles does a trapezoid have

s2008m [1.1K]

1000 meters make 1km. So let's compare that with the question.
1000m=1km
Y=33km
I represented the unknown with Y. Next, you have to cross and multiply. 33 will multiply 1,000 to give 33,000. And Y will multiply 1 to give Y. That will be;
Y=33,000m
33km makes 33,000m.
Hope that helped. Have a nice day

8 0

3 years ago

Show that the sum of two concave functions is concave. Is the product of two concave functions also concave?

spayn [35]

Answer with explanation:

Let us assume that the 2 functions are:

1) f(x)

2) g(x)

Now by definition of concave function we have the first derivative of the function should be strictly decreasing thus for the above 2 function we conclude that

$\frac{d}{dx}\cdot f(x)$

Now the sum of the 2 functions is shown below

$y=f(x)+g(x)$

Diffrentiating both sides with respect to 'x' we get

$\frac{dy}{dx}=\frac{d}{dx}\cdot f(x)+\frac{d}{dx}\cdot g(x)\\\\$

Since each term in the right of the above equation is negative thus we conclude that their sum is also negative thus

$\frac{dy}{dx}$

Thus the sum of the 2 functions is also a concave function.

Part 2)

The product of the 2 functions is shown below

$h=f(x)\cdot g(x)$

Diffrentiating both sides with respect to 'x' we get

$h'=\frac{d}{dx}\cdot (f(x)\cdot g(x))\\\\h'=g(x)f'(x)+f(x)g'(x)$

Now we can see the sign of the terms on the right hand side depend on the signs of the function's themselves hence we remain inconclusive about the sign of the product as a whole. Thus the product can be concave or convex.

8 0

3 years ago

Wrich expreson is equivalent to 4(3-6).

Korvikt [17]

You haven’t provided any option, however I think I can still help.

You can solve 4(3-6). You first deal with he parenthesis, and get 4(-3). This means that your expression is equivalent to -12.

Hope this helps :)

8 0

3 years ago

A car braked with a constant deceleration of 16ft/s2, producing skid marks measuring 200 feet before coming to a stop. How fast

Llana [10]

Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.

Step-by-step explanation:

The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,

a = - 16ft/s^2

While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.

This means that it travelled a distance,

s = 200 feet

We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.

Since the car came to a stop, its final velocity, v = 0

Applying Newton's equation of motion,

v^2 = u^2 + 2as

0 = u^2 - 2 × 16 × 200

u^2 = 6400

u = √6400

u = 80 ft/s

7 0

3 years ago

Find the prime factorization of each number.<br> 1. 50 =

Varvara68 [4.7K]

Answer:

1.5 is not a prime number

Step-by-step explanation:

7 0

3 years ago