All categories

3 years ago

2 3/10 x-5/7 y-4 5/6 y-2 4/5 x

Mathematics

1 answer:

Stels [109]3 years ago

7 0

Answer: im pretty sure this is correct

- 1/42 x (21x233y)

Step-by-step explanation:

first convert the expressions (2 3/10x x5/7 x y-2 4/5 x x )

then factor the expression (23/10 x- 5/7 y- 29/6 y- 14/5x )

then collect like terms (1/210 x 483 x - 150 y - 1015 - 588x)

factor the expression (1/210 x 105x 1165y)

Multiply reduce (1/210 x -5 (21x + 233y ))

= -1/42 x (21x233y)

You might be interested in

3x – y = -1 x – 2y = -12

Leviafan [203]

The solution to the system of equation is (2, 7)

<h3>System of equation</h3>

Given the system of equation expressed as:

3x – y = -1 * 2

x – 2y = -12 * 1

________________

6x – 2y = -2

x – 2y = -12

Subtract to have;

6x-x = -2-(-12)

5x = 10

x = 2

Substitute x = 2 into 2 to have:

2 - 2y = -12

-2y = -14

y = 7

Hence the solution to the system of equation is (2, 7)

Learn more on system of equation here: brainly.com/question/25976025

#SPJ1

8 0

1 year ago

Jenny is having a party. She has one

seropon [69]

2 .............:)
Good luck

4 0

3 years ago

Answer this equation: 4 3/5 - -3 2/5 + 3

horrorfan [7]

Answer:

Step-by-step explanation:

$4\frac{3}{5} -(-3\frac{2}{5})+3$

Negative and another negative makes a positive.

$4\frac{3}{5}+3\frac{2}{5}+3$

Add the fractions first.

$7\frac{5}{5}+3$

5/5 is equivalent to 1. 7 5/5 becomes 8.

$8+3$

Add the numbers.

$24$

I hope this helps!

6 0

3 years ago

Read 2 more answers

Consider rolling two fair dice one 3-sided the other 5-sided

Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

$1\leq x\leq 3,\quad 1\leq y \leq 5$

We have $P(X=x)=\frac{1}{3}$ and $P(Y=y)=\frac{1}{5}$ , because the dice are fair.

Now we use the assumption of independence to claim that

$P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}$

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

2 in a unique way (1+1)
3 in two possible ways (1+2, 2+1)
4 in three possible ways
5 in three possible ways
6 in three possible ways
7 in two possible ways
8 in a unique way

This implies that the probabilities of the outcomes of $W=X+Y$ are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0

3 years ago

The statement below is fallacious. Indicate which fallacy the speaker has committed:

sdas [7]

Answer:

Regression to the mean fallacy

Step-by-step explanation:

It assumes that something has returned to normal because of corrective actions taken while it was abnormal. This fails to account for natural fluctuations. It is frequently a special kind of the post hoc fallacy.

3 0

3 years ago