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bazaltina [42]
2 years ago
15

How do you solve for factoring polynomials with leading coefficient >1​

Mathematics
1 answer:
svetoff [14.1K]2 years ago
4 0

Answer: (x+5)*(x+2)

Step-by-step explanation:

1: Write as a sum

x^2+7x+10

2: Factor the expressions

x^2+5x+2x+10

3: Factor the expression

x(x+5)+2(x+5)

Answer: (x+5)(x+2)

Hope this helps!

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  x + y = 3
- x        - x
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  y - y₁ = m(x - x₁)
y - (-1) = -1[x - (-1)]
  y + 1 = -1(x + 1)
  y + 1 = -1(x) - 1(1)
  y + 1 = -x - 1
     - 1         - 1
       y = -x - 2

The answer is B.
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PLEASE HELP ASAP!!!
barxatty [35]

Answers:

  • <u>24000 dollars</u> invested at 4%
  • <u>18000 dollars</u> was invested at 7%

======================================================

Work Shown:

x = amount invested at 4%

If she invests x dollars at 4%, then the rest (42000-x) must be invested at the other rate of 7%

She earns 0.04x dollars from that first account and 0.07(42000-x) dollars from the second account

This means we have

0.04x+0.07(42000-x)

0.04x+0.07*42000-0.07x

0.04x+2940-0.07x

-0.03x+2940

This represents the total amount of money earned after 1 year.

We're told the amount earned in interest is $2220, so we can say,

-0.03x+2940 = 2220

-0.03x = 2220-2940

-0.03x = -720

x = -720/(-0.03)

x = 24000 dollars is the amount invested at 4%

42000-x = 42000-24000 = 18000 dollars was invested at 7%

----------------------

As a check, we can see that

18000+24000 = 42000

and also

0.04x = 0.04*24000 = 960 earned from the first account

0.07*18000 = 1260 earned from the second account

1260+960 = 2220 is the total interest earned from both accounts combined

This confirms our answers.

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3 years ago
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