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ASHA 777 [7]
3 years ago
11

PLEASE HELP! DUE TONIGHT

Mathematics
1 answer:
navik [9.2K]3 years ago
5 0

Answer:

B

Step-by-step explanation:

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Choose the graph that matches the following system of equations: 2x + y = −1 3x + 2y = −6
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Hi! You don't actually need to graph this nor find the intersection in order to know the answer. Through the process of elimination we can rule out incorrect answers.

Firstly, we express both equations with y on the left hand side since all choices are in that form:

y=-2x-1
y=- \frac{3}{2}x-3

Knowing these, we can immediately rule out options a, c, and d since they have the wrong equations. This will leave us with option b.

You can verify if the point of intersection provided in option b is true by plugging in the values of x and y to both equations (you will find that it is indeed true).

ANSWER: b. <span>picture of coordinate plane with line y equals negative 2x minus 1 and line y equals negative 3 halves x minus 3. They intersect at 4, negative 9.</span>
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3 years ago
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Solve the system by substitution.<br> — 6x — 5y = 11<br> x = у
Margarita [4]

Answer:

(x, y) =(-1, - 1)

Step-by-step explanation:

-Substitute the value of x

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5 0
3 years ago
What is the simplified version of 3\sqrt{135}
Aleonysh [2.5K]

Answer:

The simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

Step-by-step explanation:

The given expression is

\sqrt[3]{135}

According to the property of radical expression.

\sqrt[n]{x}=(x)^{\frac{1}{n}}

Using this property we get

\sqrt[3]{135}=(135)^{\frac{1}{3}}

\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}      [\because (ab)^x=a^xb^x]

\sqrt[3]{135}=3\times \sqrt[3]{5}     [\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]

\sqrt[3]{135}=3\sqrt[3]{5}

Therefore the simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

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3 years ago
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astraxan [27]

Answer:

8.5 per pound

Step-by-step explanation:

22.10/2.6=8.5

hope this helps!!

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3 years ago
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Which city is warmer in January.
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