4(x-3)=2(3x+1) 2 solve for x

1 answer:

3 0

Hi there!

Th' Eqn. is :-

4 (x - 3) = 2 (3x + 1)

=> 4x - 12 = 2 (3x + 1)

=> 4x - 12 = 6x + 2

Combine th' like terms :-

=> 4x - 6x = 2 + 12

=> - 2x = 14

=> x = $\dfrac {- 14}{2}$

=> x = - 7

Hence, The required answer is : x = - 7

~ Hope it helps!

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Write the data set that is shown on the dot plot in ascending order.

Lady_Fox [76]

Answer:

Step-by-step explanation:

1,2,3,3,3,3,5,6,7,10,10,10,11,11,12,12,13,13,

14,15

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3 years ago

1.What are the zeros of the polynomial function?

Lorico [155]

Let's to the first example:

f(x) = x^2 + 9x + 20

Ussing the formula of basckara

a = 1
b = 9
c = 20

Delta = b^2 - 4ac

Delta = 9^2 - 4.(1).(20)

Delta = 81 - 80

Delta = 1

x = [ -b +/- √(Delta) ]/2a

Replacing the data:

x = [ -9 +/- √1 ]/2

x' = (-9 -1)/2 <=> - 5

Or

x" = (-9+1)/2 <=> - 4
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Already the second example:

f(x) = x^2 -4x -60

Ussing the formula of basckara again

a = 1
b = -4
c = -60

Delta = b^2 -4ac

Delta = (-4)^2 -4.(1).(-60)

Delta = 16 + 240

Delta = 256

Then, following:

x = [ -b +/- √(Delta)]/2a

Replacing the information

x = [ -(-4) +/- √256 ]/2

x = [ 4 +/- 16]/2

x' = (4-16)/2 <=> -6

Or

x" = (4+16)/2 <=> 10
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Now we are going to the 3 example

x^2 + 24 = 14x

Isolating 14x , but changing the sinal positive to negative

x^2 - 14x + 24 = 0

Now we can to apply the formula of basckara

a = 1
b = -14
c = 24

Delta = b^2 -4ac

Delta = (-14)^2 -4.(1).(24)

Delta = 196 - 96

Delta = 100

Then we stayed with:

x = [ -b +/- √Delta ]/2a

x = [ -(-14) +/- √100 ]/2

We wiil have two possibilities

x' = ( 14 -10)/2 <=> 2

Or

x" = (14 +10)/2 <=> 12
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To the last example will be the same thing.

f(x) = x^2 - x -72

a = 1
b = -1
c = -72

Delta = b^2 -4ac

Delta = (-1)^2 -4(1).(-72)

Delta = 1 + 288

Delta = 289

Then we are going to stay:

x = [ -b +/- √Delta]/2a

x = [ -(-1) +/- √289]/2

x = ( 1 +/- 17)/2

We will have two roots

That's :

x = (1 - 17)/2 <=> -8

Or

x = (1+17)/2 <=> 9

Well, this would be your answers.

7 0

3 years ago

Two parallel lines are crossed by a transversal. What is the value of h? h = 60 h = 80 h = 100 h = 120

lisabon 2012 [21]

I added the diagram of the question.

Answer:
h = 60°

Explanation:
We are given that lines k and l are parallel lines.
This means that angles 120° and h are supplementary angles.
This means that their measures add up to 180°

Therefore:
180° = 120° + h
h = 180° - 120°
h = 60°

Hope this helps :)