Please help!!! I will mark you brainliast
2 answers:
Answer:5 sqrt(2)
Step-by-step explanation:
All the sides of the square are congruent by the markings. Therefore they all measure 5 and because all 4 sides are congruent it is a square. Because it is a square the corners are right angles and you can use the Pythagorean Theorem. a^2 +b^2 = c^2.
5^2 + 5^2 = x^2
25 + 25 = x^2
50= x^2
X = square root of 50
X= square root of 25 Times Square root of 2
X= 5square root of 2
Answer : 5 sqrt (2)
Step-by-step explanation:
ABCD is a square
BCD is a triangle
BC=DC=5
To find DB
Let BC= a, DC=b, BD=c.
using Pythagoras Theorem in Triangle BCD
c2 = a2+b2
c2 = 52+52
c2= 25+25
c= √(50)
c2= √(25)×√ (2)
c= √(5× 5) √(2)
c= 5√(2) or c=5sqrt(2)
Rmbr, Let BC= a, DC=b, BD=c.
You might be interested in
Answer:
I dont know how to read hindi can u pls translate it into English
Answer:
0.9
Step-by-step explanation:
range=highest-lowest
=7.1-6.2
=0.9
Answer:
c part is the answer of this question
I am assuming that PC is a radius. d = 2 * PC = 2 * 17 = 34 C = pi * d C = pi * 34 = 34pi cm if PC is a diameter, the change the 34 into 17.