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Naddik [55]
3 years ago
9

In order for a bowling ball and a soccer to accelerate the same distance the force applied ... *

Chemistry
2 answers:
rjkz [21]3 years ago
5 0

ANSWER:

The answer is A

____ [38]3 years ago
4 0
The correct answer would be A
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Glass has a specific heat of 0.16 calories/gram°C.
Sloan [31]
Calories heat added = Mass of glass times temp. increase times specific heat of glass

calories (small calories) = l.0 g x 20 degrees x .16 calories/gm/degree C = 3.2 calories
7 0
3 years ago
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(34.6785 x 5.39) + 435.12
Shalnov [3]
To solve this, we should follow order of operations. To start, we should multiply the values inside of the parentheses.

(34.6785*5.39)+435.12
186.917115+435.12

Now, we should add the 2 values we are left with together.

 186.917115
<span><u>+435.120000</u>
</span>  622.037115

Using the math above, we can see that this expression is equal to 622.037115.
5 0
4 years ago
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Please HELP, ASAP! Homework due tomorrow and I need some help.
sweet-ann [11.9K]
Ions are atoms with a charge other than zero. In a neutral atom, the number of protons (positively charged particles) in the nucleus equals the number of electrons orbiting the nucleus.
Atoms can gain or lose electrons (not protons) resulting in a net charge other than zero. Atoms which lose electrons (usually metals) become positively charges, and atoms which gain electrons (usually nonmetals) become negatively charged.
3 0
4 years ago
2ch4(g) c2h2(g) 3h2(g) describe what is happening within the system when it is at equilibrium in terms of concentrations, reacti
SashulF [63]

Balanced chemical reaction: 2CH₄(g) ⇄ C₂H₂(g) + 3H₂(g).

1) In a chemical reaction, chemical equilibrium is the state in which both reactants (methane CH₄) and products (ethyne C₂H₂ and hydrogen H₂) are present in concentrations which have no further tendency to change with time.  

2) At equilibrium, both the forward and reverse reactions are still occurring.

3) Reaction rates of the forward and backward reactions are equal and  there are no changes in the concentrations of the reactants and products.

4 0
3 years ago
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Calculate the freezing point of a 0.08500 m aqueous solution of nano3. the molal freezing-point-depression constant of water is
Citrus2011 [14]
Depression in freezing point (ΔT_{f}) = K_{f}×m×i,
where, K_{f} = cryoscopic constant = 1.86^{0} C/m,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For NaNO_{3})

Thus, (ΔT_{f}) = 1.86 X 0.0085 X 2 = 0.03162^{0}C

Now, (ΔT_{f}) = T^{0} - T
Here, T = freezing point of solution
T^{0} = freezing point of solvent = 0^{0}C
Thus, T = T^{0} - (ΔT_{f}) = -0.03162^{0}C
8 0
3 years ago
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