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Galina-37 [17]
2 years ago
9

Explain, in detail, how you convert grams of one substance to grams of something else. Be specific and include each step.

Chemistry
2 answers:
professor190 [17]2 years ago
4 0

Explanation:

First, I will assume you are asking the procedure to get mass of a substance, after we initiate a chemical reaction. If this is the case, then, let's explain it with an example:

Let's suppose we have the following reaction:

Zn + 2HCl -------> ZnCl₂ + H₂

And we part with 4.55 g of Zinc (Zn). We want to know the mass produced of ZnCl₂.

This is a simple reaction, where we only do conservation of mass. So, to get the mass of ZnCl2, we need to begin with the Zinc first, because we start with that given mass.

the mass of Zinc is 4.55 g. Chemicals reactions are better worked in moles rather than mass, because coefficients in the chemical reaction are in moles. So, in the case of the reaction (Which is already balanced):

Zn + 2HCl -------> ZnCl₂ + H₂

The number 2 that it's behind the HCl represents the theorical moles of that substance, in this case, we need 2 moles of HCl to react with only 1 mole of Zinc. It's 1 mole of Zinc because there are no numbers there, so, we always assume there's a 1 in there.

Now that we know this, let's calculate the moles of Zinc. To do that, we need the molar mass of Zinc. This can be obtained in the exercise or look the periodic table, and search for the Zinc. In this case, the molar mass of Zinc is 65.38 g/mol. So to get the moles:

n = m/MM

Replacing the data:

n = 4.55 g / 65.38 g/mol = 0.0695 moles

These are the moles of Zn reacting in the chemical reaction. Now, we should do some stechiometry. In this case, we can see that, 1 mole of zinc (In the reaction) produces 1 mole of ZnCl2, therefore the moles of Zn obtained, will be the same moles produced of ZnCl2, thus:

moles ZnCl2 = moles Zn = 0.0695 moles

Finally, with the molar mass of ZnCl2, we can calculate the mass. the molar mass of ZnCl2 is 132.29 g/mol so:

m = n * MM

Replacing:

m = 0.0695 * 132.29

<em>m = 9.19 g of ZnCl2</em>

<em>And this is the simple way to obtain the mass of a substance in a reaction</em>

VashaNatasha [74]2 years ago
3 0
First you divide the given mass of A (the initial substance) by its molar mass to get its number of moles. Then, based on a balanced chemical reaction, you divide the number of moles by the coefficient of A, then multiply by the coefficient of the product B. Finally, multiply by the molar mass of the product B (if there is a given conversion or yield %, multiply it as well), and this gives the amount of grams of the product.
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If I have 7.5 L of a gas in a piston at a pressure of 1.75 atm and compress the gas until its volume is 3.7 L, what will the new
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3.55atm

Explanation:

We will apply Boyle's law formula in solving this problem.

P1V1 = P2V2

And with values given in the question

P1=initial pressure of gas = 1.75atm

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P2=final pressure of gas inside new piston in atm

V2=final volume of gas = 3.7L

We need to find the final pressure

From the equation, P1V1 = P2V2,

We make P2 subject

P2 = (P1V1) / V2

P2 = (1.75×7.5)/3.7

P2=3.55atm

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6 0
3 years ago
Convert the composition of the following alloy from atom percent to weight percent (a) 44.9 at% of silver, (b) 46.3 at% of gold,
vesna_86 [32]

Answer:

Mass percentage of gold : 33.35%

Mass percentage of silver: 62.80%

Mass percentage of copper : 3.85%

Explanation:

N=n\times N_A

Where : N = Number of atoms

n = moles

N_A=6.022\times 10^{23} = Avogadro number

Let the total atoms present in the alloy be 100.

Atom percentage of silver = 44.9%

Atoms of of silver = 44.9% of 100 atoms = 44.9

Atomic weight of silver = 107.87 g/mol

Mass of 44.9 silver atoms = 107.87 g/mol ×  44.9 = 4,843.363 g/mol

Atom percentage of gold= 46.3%

Atoms of of gold = 46.3% of 100 atoms = 46.3

Atomic weight of gold = 196.97 g/mol

Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol

Atom percentage of copper = 8.8 %

Atoms of of copper = 8.8% of 100 atoms = 8.8

Atomic weight of copper = 63.55 g/mol

Mass of 44.9 copper atoms = 63.55 g/mol ×  8.8 = 559.24 g/mol

Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol

Mass percentage of gold :

\frac{4,843.363 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=33.35 \%

Mass percentage of silver:

\frac{9,119.711 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=62.80\%

Mass percentage of copper :

\frac{559.24 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=3.85\%

7 0
3 years ago
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