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Galina-37 [17]
3 years ago
9

Explain, in detail, how you convert grams of one substance to grams of something else. Be specific and include each step.

Chemistry
2 answers:
professor190 [17]3 years ago
4 0

Explanation:

First, I will assume you are asking the procedure to get mass of a substance, after we initiate a chemical reaction. If this is the case, then, let's explain it with an example:

Let's suppose we have the following reaction:

Zn + 2HCl -------> ZnCl₂ + H₂

And we part with 4.55 g of Zinc (Zn). We want to know the mass produced of ZnCl₂.

This is a simple reaction, where we only do conservation of mass. So, to get the mass of ZnCl2, we need to begin with the Zinc first, because we start with that given mass.

the mass of Zinc is 4.55 g. Chemicals reactions are better worked in moles rather than mass, because coefficients in the chemical reaction are in moles. So, in the case of the reaction (Which is already balanced):

Zn + 2HCl -------> ZnCl₂ + H₂

The number 2 that it's behind the HCl represents the theorical moles of that substance, in this case, we need 2 moles of HCl to react with only 1 mole of Zinc. It's 1 mole of Zinc because there are no numbers there, so, we always assume there's a 1 in there.

Now that we know this, let's calculate the moles of Zinc. To do that, we need the molar mass of Zinc. This can be obtained in the exercise or look the periodic table, and search for the Zinc. In this case, the molar mass of Zinc is 65.38 g/mol. So to get the moles:

n = m/MM

Replacing the data:

n = 4.55 g / 65.38 g/mol = 0.0695 moles

These are the moles of Zn reacting in the chemical reaction. Now, we should do some stechiometry. In this case, we can see that, 1 mole of zinc (In the reaction) produces 1 mole of ZnCl2, therefore the moles of Zn obtained, will be the same moles produced of ZnCl2, thus:

moles ZnCl2 = moles Zn = 0.0695 moles

Finally, with the molar mass of ZnCl2, we can calculate the mass. the molar mass of ZnCl2 is 132.29 g/mol so:

m = n * MM

Replacing:

m = 0.0695 * 132.29

<em>m = 9.19 g of ZnCl2</em>

<em>And this is the simple way to obtain the mass of a substance in a reaction</em>

VashaNatasha [74]3 years ago
3 0
First you divide the given mass of A (the initial substance) by its molar mass to get its number of moles. Then, based on a balanced chemical reaction, you divide the number of moles by the coefficient of A, then multiply by the coefficient of the product B. Finally, multiply by the molar mass of the product B (if there is a given conversion or yield %, multiply it as well), and this gives the amount of grams of the product.
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Which of the following aqueous solutions will have the lowest freezing point? a. 0.75 m (NH4)3PO4 b. 1.0 m CaSO4 c. 1.0 m LiCl d
Nataly [62]

Answer: a. 0.75m (NH4)3PO4 will have the lowest freezing point .

Explanation: Freezing point decreases as the concentration of the solute substance increases. Assuming the same solvent for all of them, for instance water.

∆T= i.Kf.b

∆T= freezing point depression

i= vant Hoff factor

Kf= molality

Assuming water to be the solvent for all Kf=1.86°C/M

VANT HOFF FACTORS :

For (NH4)3PO4

This has 3 ionic bonding and 1 covalent bonding making it 4 bond

Therefore i=4

For CaSO4

This has 1 metallic bond and 1 covalent bond making it 2 bond.

Therefore i=2

For LiCl

This has 1 metallic bond and 1 non metallic bond making it 2 bond.

Therefore i=2

For CH3OH

This has only 1 covalent bond.

Therefore i=1

MOLALITY:

(NH4)3PO4 = 0.75M

CaSO4= 1.0M

LiCl= 1.0M

CH3OH= 1.5M

FREEZING POINT DEPRESSION:

For (NH4)3PO4

∆T= 4×0.75×1.86=5.58°C

For CaSO4

∆T= 2×1.0×1.86=3.72°C

For LiCl

∆T = 2×1.0×1.86= 3.72°C

For CH3OH

∆T= 1×1.5×1.86=2.79°C

REMEMBER THE HIGHER THE FREEZING POINT DEPRESSION THE LOWER THE FREEZING POINT.

FREEZING POINT DEPRESSION IS THE CHANGE IN THE FREEZING POINT PROPORTIONAL TO THE AMOUNT OF SOLUTE ADDED THE THE SOLUTION.

THEREFORE THE ONE WITH THE LOWEST FREEZING POINT IS (NH4)3PO4

4 0
4 years ago
The enthalpy of fusion of H2O (s) at its normal melting point is 6.01 kJ/mol. What is the entropy change for freezing 1 mole of
Rom4ik [11]

Answer:

22.01J/Kmol

Explanation:

The parameters given in this question are;

Enthalpy (H) = 6.01 kJ/mol.

Number of moles = 1

Entropy change (S) = ?

The formular relationship between entropy and enthalpy is given as;

ΔS=ΔH/T

Temperature for water at freezing point = 0C + 273 = 273 K (converting to Kelvin)

ΔS = 6.01/273

ΔS = 0.0220kJ/Kmol

ΔS = 0.02201 * 1000 = 22.01J/Kmol

3 0
3 years ago
Which compound could serve as a reactant in a neutralization reaction ?
Veseljchak [2.6K]
 The   compound that  could serve  as  a reactant   in the neutralization reaction is    H2SO4
     
  Explanation
   Neutralization reaction occur  between an acids  and a base. H2SO4             (  sulfuric acid)  is  a strong  acid.  It can be neutralized by  strong base such as NaOH ( sodium  hydroxide)

  Example of neutralization reaction is

2NaOH + H2SO4 → Na2SO4  + 2H2O
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zlopas [31]

Answer:

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Help please i’ll give extra points
joja [24]

Answer:

okay no problem

I will give

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