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4 years ago

Help with math. Only one question.

Mathematics

1 answer:

Dimas [21]4 years ago

3 0

Idk what the answer is

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A birthday cake was cut into equal pieces, and four pieces were eaten. The fraction below shows how many pieces were left. Accor

zmey [24]

4 were not eaten from the cake

4 0

4 years ago

I WILL MARK U AS A BRAINLIEST! Please help question on the picture.

tester [92]

Answer:

just wanted to let you know you didn't attach a picture would love to answer question in comments once I can see the photo

6 0

3 years ago

Please help as soon as possible.. I don’t understand this.

damaskus [11]

Answer:

45ft squared

Step-by-step explanation:

you multiply 3 by the radius which is 15

that gives you a total of 45

3 0

3 years ago

Find the 75th term of the arithmetic sequence -17, -13, -9....

Sphinxa [80]

Answer:

The 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

Step-by-step explanation:

Given the sequence

$-17, -13, -9....$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$-13-\left(-17\right)=4,\:\quad \:-9-\left(-13\right)=4$

The difference between all the adjacent terms is the same and equal to

$d=4$

The first element of the sequence is:

$a_1=-17$

now substitute $d=4$ and $a_1=-17$ in the nth term of the sequence

$a_n=a_1+\left(n-1\right)d$

$a_n=4\left(n-1\right)-17$

$a_n=4n-21$

Now, substitute n = 75 in the $a_n=4n-21$ sequence to determine the 75th sequence

$a_n=4n-21$

$a_{75}=4\left(75\right)-21$

$a_{75}=300-21$

$a_{75}=279$

Therefore, the 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

3 0

3 years ago

Square root of 49/196

Andru [333]

$\sqrt{ \frac{49}{196} } = \frac{ \sqrt{49} }{ \sqrt{196} } = \frac{7}{14} = \frac{1}{2}$

4 0

3 years ago