All categories

2 years ago

I need to know what the x and y intercepts are for these problems. if you could show work i would appreciate it.

Mathematics

1 answer:

Tomtit [17]2 years ago

3 0

Answer:

x = (2,0)

y = (0,-8)

x = (-2,0)

y = ( 0, 2)

x = ( 4,0)

y = ( 0, -16)

Step-by-step explanation:

aIll do one equation as an example

f(x) = 4x -8

y = 4x - 8

since its an intercept you know the x, for the y intercept will be zero and vice versa. Its like this cause its on the axis.

So you only need to figure out the y for the y intercept and the x for the x intercept.

- 4x + y = -8

after changing the equation to standar form you then ignore the x base so, 4x to get the y intercept.

- 4x + y = -8 becomes y = - 8 then you add the 0 for the coordinate

y = -8 becomes (0,-8)

f(x) = 4x -8

y = 4x - 8

- 4x + y = -8

y = - 8

(0,-8)

f(x) = 4x -8

y = 4x - 8

- 4x + y = -8

-4x = -8

x = 2

(2, 0)

sorry im not really good at explaining lol

can g et a brainliest for effort at least 5 points isnt much

You might be interested in

In△XYZ , XY¯¯¯¯¯¯=7in , YZ¯¯¯¯¯=5in , and XZ¯¯¯¯¯=4in . This triangle is reflected across the x-axis to result in △X'Y'Z' . Whic

ki77a [65]

Answer:

Step-by-step explanation:

Reflection is a transformation that preserves lengths.

Triangle XYZ, with side lengths XY = 7 in, YZ = 5 in, XZ = 4 in, is reflected across the x-axis to result in △X'Y'Z'.

This means that corresponding sides have the same lengths:

XY = X'Y' = 7 in;
XZ = X'Z' = 4 in;
YZ = Y'Z' = 5 in.

Find the perimeters of both triangles:

$P_{XYZ}=XY+XZ+YZ=7+4+5=16\ in\\ \\P_{X'Y'Z'}=X'Y'+X'Z'+Y'Z'=7+4+5=16\ in$

Hence, only option B is true.

8 0

3 years ago

Please answer this correct answer now fast

lutik1710 [3]

Answer:

WX = 8 mm

Step-by-step explanation:

To be able to solve for WX, we need to first find the size of angle $\angle z$ .

We use the law of sines in the blue triangle to do such:

$\frac{sin(z)}{11} =\frac{sin(133)}{20} \\sin(z)=\frac{11\,sin(133)}{20} \\sin(z)=0.4022$

Now we can use this value in the larger right angle triangle where WX is the opposite side to angle $\angle z$ , and the 20 mm side is the hypotenuse:

$sin(z)=\frac{opposite}{hypotenuse} \\sin(z)=\frac{WX}{20}\\0.4022=\frac{WX}{20}\\WX=20\,(0.4022)\\WX=8.044\,\,mm$

which rounded to the nearest integer gives

WX = 8 mm

3 0

3 years ago

Write the decimal as a percent. 0.35=__%

Alja [10]

Answer:

35%

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Is(5, 6)a solution to the inequality y < 2x + 4 ?

Diano4ka-milaya [45]

Answer:

yes

Step-by-step explanation:

y < 2x +4

6 < 2·5 +4

6 < 14

4 0

3 years ago

What is the value of x? Round to the nearest tenth(1 decimal place)

liraira [26]

Answer:

x ≈ 15.0 ft

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Trigonometry

tan∅ = opposite over adjacent

Step-by-step explanation:

Step 1: Define

Angle = 28°

Opposite leg of angle = 8 ft

Adjacent leg of angle = x ft

Step 2: Find x

Substitute: tan28° = 8/x
Multiply x on both sides: xtan28° = 8
Divide tan28° on both sides: x = 8/tan28°
Evaluate: x = 15.0458
Round: x ≈ 15.0 ft

6 0

3 years ago