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2 years ago

Perfect square trinomial conditions

Mathematics

1 answer:

aev [14]2 years ago

4 0

Step-by-step explanation:

step 1. an example of difference of squares (dos) is (x + y)(x - y) = x^2 - y^2.

step 2. dos must have only 2 square rootable terms and a "-" between them.

step 3. 196x^2 - 121y^2 = (14x + 11y)(14x - 11y) works!

step 4. 5x^2 - 245 = 5(x^2 - 49) = 5(x + 7)(x - 7) works!

step 5. 27w^5 - 75w = 3w(9w^4 - 25) = 3w(3w^2 + 5)(3w^2 - 5) works!

step 6. x^4 - 100y^2 = (x^2 - 10y)(x^2 + 10y) works!

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Step-by-step explanation:

π Is a constant. It always has the same value.

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2 years ago

Solving Square Roots Worksheet (x - k)^2 : Part 1

iVinArrow [24]

Answer:

1. x = +/- 2 $\sqrt{2}$ - 7

2. x = $3$ +/- $2i\sqrt{3}$

3. n = $2$ +/- $i\sqrt{2}$

Step-by-step explanation:

1. Divide both sides by 2: (x + 7)^2 = 8

Square root both sides: x + 7 = +/- 2 $\sqrt{2}$

Subtract 7 from both sides: x = +/- 2 $\sqrt{2}$ - 7

2. Square root both sides: x - 3 = $\sqrt{-12}$

Since there is a negative inside the radical, we need to have an imaginary number: $i=\sqrt{-1}$ . So, $\sqrt{-12} =i\sqrt{12} =2i\sqrt{3}$

Add 3 to both sides: x = $3$ +/- $2i\sqrt{3}$

3. Divide by -5 from both sides: (n - 2)^2 = -2

Square root both sides: n - 2 = $\sqrt{-2}$

Again, we have to use i: $n-2=\sqrt{-2} =i\sqrt{2}$

Add 2 to both sides: n = $2$ +/- $i\sqrt{2}$

Hope this helps!

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Kisachek [45]

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Answer:

1a: 1,000,000

2a: 1

3a: 6

4a: 0

5a: 1

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7a: 9

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We look for where $x=7$ . The way you find the answer is first, find the point $(0, 7)$ . Draw a line straight up and down, and see where that line intersects the function. Those intersection points are your answer(there will always be only 1 for a function, but if a graph isn't a function, there might be more than 1).

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