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tester [92]
3 years ago
11

a retailer buys a coat in nulk at a unit price of $45. the coat is marked up %28 percent to sell in the store. Whats the price o

f the coat in the store
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

$57.6

Step-by-step explanation:

128/100*45

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What is the radius of a hemisphere with a volume of 885 in^3, to the nearest tenth of<br> an inch?
victus00 [196]

Answer:

The desired radius is r = 7.5 inches

Step-by-step explanation:

The formula for the volume of a sphere of radius r is V = (4/3)πr³.  A hemisphere is half a full sphere, so the formula for the volume of a hemisphere of radius r is (4/3)(1/2)πr³, or (2/3)πr³.

We know that the volume of the hemisphere is 885 in³:

885 in³ = (2/3)πr³ and need to solve this first for r³ and then for r.

This is equivalent to:

885 in³ = (2π/3)r³.

We can now isolate r³ by multiplying both sides of this equation by (3 / [2π]):

(3 / [2π])(885 in³) = (3 / [2π])(2π/3)r³ = r³

Then r³ = 422.556 in³

Finally, we find the desired hemisphere radius by taking the cube root of both sides of the above equation:

r = ∛(422.556 in³) = 7.5 in (which is to the nearest tenth of an inch)

The desired radius is r = 7.5 inches

4 0
2 years ago
What is the product of a+3 and −2a2+15a+6b2?
Lady bird [3.3K]

Answer:

c. 2a3+9a2+45a+6ab2+18b2

Step-by-step explanation:

(a+3) + (−2a2+15a+6b2)

Using distributed p. with and a and 3

a(−2a2) + a(15a) +a(6b2)        and       3(−2a2) + 3(15a) + 3(6b2)

= -−2a3 + 15a2 + 6ab2                          = -6a2 + 45a + 18b2

Now add like terms and put in standard form.

15a2+(-6a2) = 9a2  

And equals

-2a3 + 9a2+45a+6ab2+18b2

Trust me I took the test and got 100%

Your welcome,

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3 years ago
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Romashka-Z-Leto [24]

Answer:No it is not proportional

Step-by-step explanation:

The reason non proportional is not proportional is bc it's not proportional.

3 0
3 years ago
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5c + 16,5 = 13,5 + 10c5 c+1 6 . 5=1 3 . 5+1 0 c5
marysya [2.9K]

Answer:

tht looks so difficult

Step-by-step explanation:

5 0
3 years ago
Help pls my test is about to end​
azamat

Answer:

what is your question ???

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