Answer:His net profit is $300
Step-by-step explanation:
Total amount borrowed is $2000. The loan has an annual interest rate of 8 percent. It was borrowed for only six months. This amount of interest paid will be determined using the simple interest formula,
I = PRT/100
Where
P = principal = $2000
R = rate = 8%
T = time = 6 months = 0.5 years
I = interest
I = (2000× 8 × 0.5)/100 = 80
The interest that will be paid for $2000 is $80
Total amount paid back is 2000 + 80 = $2080
He bought 100 shares at $60.00 per share and the total is $6,000
He sold the stock for $65 per share. This means that the total amount for which he sold the stock is 65×100 = $6500.
To determine his profit, we would subtract the total amount paid back due to the loan, the commission and his initial cash from the total amount recovered from selling his stock.
It becomes
6500 - ( 2080 + 120 + 4000)
= 6500 - 6200 = 300
His net profit is $300
Answer:
Step-by-step explanation:
9.50 ÷ 1 = 9.50
18 ÷ 2 = 9.50
28.50 ÷ 3 = 9.50
38 ÷ 4 = 9.50
47.50 ÷ 5 = 9.50
Direct variation is the relationship between tow variables in which one is a constant multiple of other.
Here, If we take hours worked as 'x' and pay as 'y',
y = 9.50*x
Answer:
X=1÷2,Y=32°
Step-by-step explanation:
in right angled traingleRST
<R+<T<S=180(INTERIOR ANGLE OF TRAINGLE)
Y-2+90+60=180(S=60°BEING ONE ANGLE OF EQUILATERAL TRAINGLE)
Y+148=180
Y=180-148=32
NOW,
UT=5X(RT BISECTS TS AND UT EQUALLY)
RU=US(SIDE OF EQUILITERAL TRAINGLE IS EQUAL)
8X+1=UT+TS
8X+1=5X+5X
1=10X-8X
1=2X
X=1/2
Surface area of one face = 9x9 = 81
total no. of faces = 6
total surface area of prism = 81 x 6 = 486in.
For
the first question; we have a problem dealing with translations.
Our goal is to translate
the word problem into an algebraic one. So our numbers are
60, 2, and 5. Our variable, or the letter holding the unknown
number's place
value, is
N. <span>
</span>The
problem states that 60 is MORE THAN the PRODUCT of 5 and N. Focus
on the words I bolded and capitalized. These are your key words that
tells you what operations
you need to use. Note that 'product' signals the operation of
multiplication (Since the answer you get from multiplying numbers is
called the 'product'.) and
'more than' signals the operation of addition (Because you are left
off with more than you originally had before adding). <span>
</span>Now
that we know that our algebraic expression contains multiplication,
addition, letter N and the numbers 2 and 5; we can start plugging the
numbers in.<span>
</span>60
= 2 (more than) + (product of) 5N. The answer for the first
attachment is
B. <span>
</span>_____________________________________________________________<span>
</span>All
we need to do for the AB problem (Question 25 on your material) is
solve AB.<span>
</span>Note
1: When a problem has no operation separating two letters or numbers,
this means multiplication.<span>
</span>Note
2: A and B are variables. Variables are letters that stand for and
hold the place of our unknown quantities. However, the values are not
unknown anymore given the fact that the question tells us that A= 42
and B = 2. Thus we substitute A with 42 and B with 2, then work from
there. 42 * 2 =84. Answer = A.
____________________________________________________________________
And
finally, for question 26, we use PEMDAS. P = parenthesis (), E =
exponent x^2, M/D = x or /, A/S means + or subtraction.
According
to PEMDAS, we first solve what's parenthesis, which is 77 – 32.
Using mental math, 77 – 32 = 45. ( 7 – 3 = 4 and 7 – 2 = 5.). 5/9
* 45 is what we have left. 5 divided by 9 =0.5555555555555556.
0.5555555555555556 * 45 = 25. Answer is D.
