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Basile [38]
3 years ago
13

I need help, 15 points!

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

3(a + 5b + 7c) and 2x(2 + 5y + 11z)

Step-by-step explanation:

3a + 15b + 21c

3(a + 5b + 7c)

4x + 10xy + 22xz

2x(2 + 5y + 11z)

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Simplify: ∣−4+7/3+∣13−(−7)/5
mamaluj [8]
241/15 , if I’m not mistaken would be the answer
4 0
3 years ago
3. A pattern of growth with a constant value added is ________________________________ .
Sidana [21]

Linear

Step-by-step explanation:

because a linear changes at a constant rate and an exponential changes by a common ratio

6 0
4 years ago
If the speed of a is 3 ft/s up and is increasing at 4 what is the instantaneous speed and acceleration
Tasya [4]
Sorry I'm in high school.. but according to my physics class, the instantaneous speed is when t (time) is 0, or whatever you'd use (like x).. anyways, when t=0, the instantaneous speed would be 3 ft/s, and the instantaneous acceleration is 0.
6 0
3 years ago
Find the remaining trig values of θ if <br> cotθ = − 3/5 and csc θ &lt; 0 .
EastWind [94]

Answer:

1 Answer. Aviv S. The value of tan(π3) is √3 .

Step-by-step explanation:

3 0
3 years ago
Two cars are driving towards an intersection from perpendicular directions.
FrozenT [24]

For a better understanding of the solution provided here please find the diagram in the attached file.

In the diagram, A is the intersection. B is the position of the first car and C is the position of the second car. As can be clearly seen, as per the directions given in the question, the cars and the intersection make a right triangle.

The distance between the first car and the intersection is x and the distance between the second car and the intersection is y. The distance between the two cars is depicted by s. As we can see, s is the hypotenuse of the right triangle. At the given instance the distances are 8 meters and 6 meters respectively. Thus, by the Pythagorean Theorem the hypotenuse will be:

s=\sqrt{8^2+6^2}= \sqrt{100}=10...............(Equation 1)

Now, we know that at any instant the Pythagorean Theorem holds and so we will have, in general:

s^2=x^2+y^2

Now, implicitly differentiating the above formula with respect to time, we get:

2s\frac{ds}{dt}=2x \frac{dx}{dt}+2y \frac{dy}{dt}

This can be further simplified by dividing both the sides by the common factor 2 as:

s\frac{ds}{st}=x \frac{dx}{dy}+y\frac{dy}{dt}.................(Equation 2)

As we can see from the questions and the diagram, \frac{dx}{dt}=-2 m/s and \frac{dy}{dt}=-9 m/s. The negative sign is there because the distances y and x are reducing as the cars approach the intersection.

Applying this knowledge to (Equation 2) along with the fact that as per (Equation 1), s=10, we get (Equation 2) to become:

10\times \frac{ds}{dt}=8\times -2+6\times -9=-70

Therefore, \frac{ds}{dt}= \frac{-70}{10}=-7 m/s

Thus,  the rate of change of the distance between the cars at the given instant (in meters per second) is -7.

Therefore, out of the given options, option D is the correct one.


4 0
3 years ago
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