Question

Help please !!!!!!!!!!!

Answer 1

Answer:

See below for answers and explanations to the first 5 problems

Step-by-step explanation:

Problem 1:

cos(x) = 2/3

sec(x) = ?

sec(x) = 1/cos(x)

sec(x) = 1/(2/3)

sec(x) = 3/2

Problem 2:

sinβ = -5/6

cscβ = ?

cscβ = 1/sinβ

cscβ = 1/(-5/6)

cscβ = -6/5

Problem 3:

secφ = 2

tanφ = √3

sinφ = ?

secφ = 1/cosφ

tanφ = sinφ/cosφ

tanφ = sinφ/cosφ

tanφ = sinφ(1/secφ)

√3 = sinφ(1/2)

2√3 = sinφ

Problem 4:

secθ = 8

tanθ = 3√7

cscθ = ?

secθ = 1/cosθ

tanθ = sinθ/cosθ

cscθ = 1/sinθ

tanθ = sinθ/cosθ

tanθ = sinθ(1/cosθ)

3√7 = sinθsecθ

3√7 = sinθ(8)

(3√7)/8 = sinθ

cscθ = 1/sinθ

cscθ = 1/((3√7)/8)

cscθ = 8/(3√7)

cscθ = (8√7)/21

Problem 5:

sinθ = 2/√5

cosθ = 1/√5

tanθ = ?

tanθ = sinθ/cosθ

tanθ = (2/√5)/(1/√5)

tanθ = (2/√5)(√5)

tanθ = 2