They had 56 lives in total
Explanation: if there were thirteen friends to begin with and six quit that would leave them with 7 friends. If those seven remaining friends each had 8 lives, you multiply those 7 friends by 8 lives which would get 56.
If all thirteen friends were still in the game then they would have 104 lives all together.
Answer:
47 meetings
Step-by-step explanation:
1. You know the company generates 100,000 dollars in profits, and pays 50,000 dollars to host the event, therefore, subtract both numbers to determine how much profit they make.
100,000 - 50,000 = 50,000 dollars
2. You now know that company generates 50,000 dollars in profits for each meeting
3. You also know that the company is aiming for a profit of 2.35 million, so you would divide the the goal by the total profits per meeting
2,350,000/50,000 = 47
It takes 47 meetings for the company to reach their goal.
3) x² - 121 = 0
x² = 121
x' = +√121
x' = 11
_______________
x'' = - √121
x'' = -11
Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)
4) 4x² + 144 = 0
4x² = -144
x² = -144 / 4
x² = -36
x = √-36
No solution ⇒ S = ∅
5) z²+10z+21 = 0
Δ = 10² - 4(1)(21)
Δ = 100 - 84
Δ = 16
x' = (-10+4) / 2 = -6/2 = -3
x'' = (-10-4) / 2 = -14/2 = -7
Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
So you would take 3x1+2 that gives you 5 and you would keep the same denominator and so that would give you 5/3 then do the same to the other side which would give you 5/4 then you would times it and that would give you 2 1/12
Answer:
Hey there!
The first equation has no solutions, as it is parallel lines.
The second equation has infinitely many solutions, as it is basically the same line, and the two lines intersect at infinite points.
The third equation is just one solution.
Let me know if this helps :)
