Answer:
1/2
Step-by-step explanation:
3 * 1/6 = 3/6
Which can simplify to 1/2 if you divide the top and bottom by 2.
Answer:
this wont work
Step-by-step explanation:
kidding will type awnser shortly
Answer:
Total 25.45 hours will be taken to empty the pool.
Step-by-step explanation:
Time taken by large pumpkin to empty the pool=40 hours
Time taken by the smaller pumpkins to empty the pool=70 hours
Amount of pool emptied by large pumpkin in one hour=
Amount of pool emptied by small pumpkin in one hour=
Amount of pool emptied in one hour if both pumpkins work together=
+ 
=
Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie . 
Total 25.45 hours will be taken to empty the pool.
we have

Solve for c--------> that means that clear variable c
so
Divide by
both sides

Adds
both sides

Multiply by
both sides
![a[(R/5)+0.3]=c](https://tex.z-dn.net/?f=a%5B%28R%2F5%29%2B0.3%5D%3Dc)
so
![c=a[(R/5)+0.3]](https://tex.z-dn.net/?f=c%3Da%5B%28R%2F5%29%2B0.3%5D)
therefore
<u>the answer is</u>
![c=a[(R/5)+0.3]](https://tex.z-dn.net/?f=c%3Da%5B%28R%2F5%29%2B0.3%5D)