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o-na [289]
3 years ago
12

James spent $20.16 on comic books. Each comic book cost $0.72. After he read the comic books, James sold each one for $0.20 less

than he paid for it. What is the total amount of money that James received from selling his comic books? Enter your answer in the box.
Mathematics
1 answer:
adell [148]3 years ago
8 0

Answer:

$14.56

Step-by-step explanation:

<u><em>Steps to answering this question </em></u>

  1. Determine the total number of comics bought. This can be done by dividing the total amount spent on comics by the unit price of a comic
  2. Determine the selling price of the comic
  3. multiply the amount of comics bought by the selling price

the total number of comics bought = total amount spent on comics / per unit price of comics

$20.16 / $0.72 = 28

selling price = 0.72 - $0.20 = $0.52

Total amount received = selling price x total comics bought

$0.52 x 28 = $14.56

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I need thee answer :)
sladkih [1.3K]

Answer:

12%

Step-by-step explanation:

75-75*0.2=60

60+60*0.1=66

66/75=0.88=88%

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3 years ago
John has an object suspened in the air it has a mass of 50kg and is 50 meters above the ground calcuate the objcects ising poten
satela [25.4K]

Answer: John has an object suspended in the air. It has a mass of 50 kilograms and is 50 meters above the ground. Calculate the object's potential energy.

Step-by-step explanation:

Calculate the potential energy for a 2 kg basketball dropping from a height of 3.5 meters with a velocity of 9.8 m/sec².

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3 years ago
Choose the best coordinate system to find the volume of the portion of the solid sphere rho &lt;_4 that lies between the cones φ
MrRissso [65]

Answer:

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

Step-by-step explanation:

We get the limits of integration:

R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq  4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace

We use the spherical coordinates and  we calculate a triple integral:

V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4  \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}}  \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\

we get:

V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

4 0
3 years ago
A package of 5 pairs of insulated socks costs ​$39.45. What is the unit price of the pairs of socks​?
Brums [2.3K]

Answer:

7.89

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square?
garri49 [273]

<u>Given</u>:

Given that the radius of the circle is 2 inches.

We need to determine the area of the remaining square.

<u>Area of a square:</u>

Given that each circle has a radius of 2 inches.

Then, the diameter of each circle is 4 inches.

Hence, the side length of the square is 2 × 4 = 8 inches.

The area of the square is given by

A=s^2

A=8^2

A=64 \ in^2

Thus, the area of the square is 64 square inches.

<u>Area of the four circles:</u>

The area of one circle is given by

A=\pi r^2

Substituting r = 2, we have;

A=4 \pi

Thus, the area of one circle is 4π in²

The area of 4 circles is 4 × 4π =16π in²

Hence, the area of the 4 circles is 16π in²

<u>Area of the remaining square:</u>

The area of the remaining square is given by

Area = Area of the square - Area of four circles.

Substituting the values, we get;

Area = 64-16 \pi

Thus, the area of the remaining square is (64 - 16π) in²

Hence, Option c is the correct answer.

5 0
3 years ago
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