Here's one way--- 1 half dollar, 2 quarters, 10 pennies
Distance = speed x time
Distance travelled by car A when car B started = 60 x 2 = 120 miles
Number of miles remaining at the time car B started = 400 - 120 = 280 miles.
At time of their meeting both cars has travelled a combined distance of 280 miles and has spent the same time.
Let t be the time they travelled together before they meet, then the sum of the distance travelled by car A and car B is 280miles.
60t + 80t = 280
140t = 280
t = 280/140 = 2 hours
After 2 hours car A has travelled a further 60 x 2 = 120 miles and car B has travelled 80 x 2 = 160 miles.
Total distance travelled be car A is 120 + 120 = 240 miles
Midpoint of the journey = 400/2 = 200 miles
Therefre, at the time they met, the were 40 miles from the midpoint and they are close to San Francisco.
Answer:
35z at the power of 6 times d at the power of 11
Step-by-step explanation:
add the z's power together then the d's power
Answer:
see explanation
Step-by-step explanation:
(1)
Note the ratio of consecutive terms is common, that is
2000 ÷ 2500 = 0.8
1600 ÷ 2000 = 0.8
1280 ÷ 1600 = 0.8
This indicates that the series is geometric with common ratio r = 0.8
The sum to n terms of a geometric series is
= 
← a is the first term
Here a = 2500 and r = 0.8, thus
= 
= 
= 8404
(2)
Note the difference in consecutive terms is common, that is
3 - 11 = - 8
- 5 - 3 = - 8
- 13 - (- 5) = - 8
This indicates that the series is arithmetic with common difference d = - 8
The sum to n terms of an arithmetic series is
= a₁ + (n - 1)d ← a₁ is the first term
Here a₁ = 11 and d = - 8, thus
= 11 + (13 × - 8) = 11 - 104 = - 93
Answer: qwrjbnqwuhfqwuyfqgfyhf m,gnkewnb nmewg
Step-by-step explanation:
asbfjhfbhwfqhwabfv qwfvqwghfvqwygvqwfgyqwf
