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Neko [114]
2 years ago
10

Please can someone help me with this question.

Mathematics
1 answer:
saw5 [17]2 years ago
8 0

Answer:

Step-by-step explanation:

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Question:Find the area of he trapezoid by decomposing it into other shapes.
Ad libitum [116K]

Answer:

D) 171 cm²

Step-by-step explanation:

You don’t actually need to decompose it.  You could just do it as a trapezoid:

(15+23)/2=19

19x9=171

If you want to decompose it into 2 triangles and a rectangle:

10=15x9=135

1/2(3)(9)=13.5

1/2(5)(9)=22.5

135+13.5+22.5=171 also

8 0
2 years ago
What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
2 years ago
Read 2 more answers
How many times can i write the number 6 on 7 cards
Eva8 [605]

Ummmmmmmmmm 7 i think that is the wright answer


5 0
3 years ago
Seven more than the product of 7 and a number
n200080 [17]
Answer:

7 + 7n

Explanation:

Seven more (7 plus) the product of 7 and a number (seven times n) = 7 plus 7n
8 0
2 years ago
Read 2 more answers
Select the correct answer.<br> A and АВ:<br><br> Which matrix is matrix B?
Kruka [31]

Answer:

Option B

Step-by-step explanation:

Looking at the options, option B is correct because when multiplying it by matrix A, it yields the matrix AB as follows;

First row of A multiplied by first column of matrix in option D;

(1 × -1) + (0 × 0) + (0 × 0) = -1 which corresponds to the first number on the first row of Matrix AB

Since majority of matrix AB are zero, I will just prove the ones that are not zero.

Thus;

Second row of matrix A is multiplied by second column of matrix in option D;

(0 × 0) + (-1 × -1) + (0 × 0) = 1 which is same as 2nd number on second row in matrix AB

Lastly, third row of matrix A is multiplied by third column of matrix in option D;

(0 × 0) + (0 × 0) + (1 × -1) = -1 which is same as third number in third row in matrix AB

5 0
2 years ago
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