Help me with #9 please!!
1 answer:
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Let's solve this problem step-by-step.
STEP-BY-STEP EXPLANATION:
Let's first establish that the origin is always ( 0, 0 ).
Next, as shown in the diagram attached, we can establish that there is a right-angle triangle formed when we connect the different points given from the problem. We can use this to solve the problem.
As the shape is a right-angle triangle, we can use Pythagoras' Theorem which is as follows:
a^2 + b^2 = c^2
Where c = hypotenuse of the right-angle triangle
Where a and b = other two sides of the right-angle triangle which aren't the hypotenuse
From this, we will substitute the values from the problem into Pythagoras' Theorem.
a^2 + b^2 = c^2
a = 12
b = 5
c = distance from the origin = d
THEREFORE:
( 12 )^2 + ( 5 )^2 = d^2
d^2 = 12^2 + 5^2
d^2 = 144 + 25
d^2 = 169
d = square root of ( 169 )
d = 13
FINAL ANSWER:
Therefore, the point ( 12, 5 ) is 13 units from the origin.
Hope this helps! :)
Have a lovely day! <3
STEP-BY-STEP EXPLANATION:
Let's first establish that the origin is always ( 0, 0 ).
Next, as shown in the diagram attached, we can establish that there is a right-angle triangle formed when we connect the different points given from the problem. We can use this to solve the problem.
As the shape is a right-angle triangle, we can use Pythagoras' Theorem which is as follows:
a^2 + b^2 = c^2
Where c = hypotenuse of the right-angle triangle
Where a and b = other two sides of the right-angle triangle which aren't the hypotenuse
From this, we will substitute the values from the problem into Pythagoras' Theorem.
a^2 + b^2 = c^2
a = 12
b = 5
c = distance from the origin = d
THEREFORE:
( 12 )^2 + ( 5 )^2 = d^2
d^2 = 12^2 + 5^2
d^2 = 144 + 25
d^2 = 169
d = square root of ( 169 )
d = 13
FINAL ANSWER:
Therefore, the point ( 12, 5 ) is 13 units from the origin.
Hope this helps! :)
Have a lovely day! <3
Because 
is increasing, you know that 
, which means 
must be concave upward over its domain, so A is strue.
By the same fact above, you also know that D must be true.
Relative extrema occur for points where
, and you know that the graph of crosses the x-axis at 
, so this is also true.
That leaves B. Why is it false? Inflection points occur at points where
, where the sign of 
changes to either side of 
. But you know that is always true, so there is no such that makes .
By the same fact above, you also know that D must be true.
Relative extrema occur for points where
That leaves B. Why is it false? Inflection points occur at points where
Substitute -2 for x
Hope it helps
Please give brainliest