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stellarik [79]
3 years ago
5

5

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0
我們的確認為自己沒有把握時間前往取回本書就要開始有什麼關係,他們會不會覺得自責的
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Which number is a solution of the inequality? x(7 – x) > 8
m_a_m_a [10]
X(7-x)>8  perform indicated multiplication on left side

7x-x^2>8  divide both sides by -1

x^2-7x<-8  halve the linear coefficient, square it, and add it to both side ie (-7/2)^2=12.25

x^2-7x+12.25<4.25 now the left side is a perfect square

(x-3.5)^2<4.25  take the square root of both sides

x-3.5<±√4.25  add 3.5 to both sides

x<3.5±√4.25

So x>3.5-√4.25 and x<3.5+√4.25  or if you want approximations

x>1.44 and x<5.56 or in interval notation:

x=(1.44, 5.56)  (to nearest hundredths)
7 0
3 years ago
Read 2 more answers
Please tell me the answer! I'm crying in confusion! :(
soldier1979 [14.2K]
Well, if 14 ounces of the drink has 10 and a half teaspoons of sugar, and the question asks how much sugar is in 1 ounce, the equation would be, 14 / 10.5 = 1. (repeating) 3 so...  1 and 1/3 teaspoons of sugar. I hope that helps! Please mark as brainliest! :)
5 0
3 years ago
Malik got a 200 cafe gift on January 1. He always orders decaf mochas which cost 5 each. At the end of January, maliks gift card
Over [174]

Answer:

200 - 5x = 125

Step-by-step explanation:

Let the number of orders made by Malik in the month of January = x

Each order costs = $5

Total cost of decaf mochas in one order = $5x

Malik had cake gift on 1st of January = $200

Amount of money left with Malik at the end of January = $125

Therefore, equation representing this situation will be,

200 - 5x = 125

8 0
3 years ago
Complete the steps to factor the polynomial by grouping.<br>P(x) = x3 + 5x2 – x – 5
ahrayia [7]
<span>P(x) = x</span>³<span> + 5x</span>²<span> – x – 5

P(x) = x</span>²(x+5) - (x + 5)

P(x) = (x + 5)(x² - 1)

P(x) = (x + 5) (x + 1)(x -1)
6 0
4 years ago
Read 2 more answers
4. If A ABC = ADEF, mZ A = 50°, and mZE= 30°, what is m 2 C?
zimovet [89]

Answer:

100

Step-by-step explanation:

50+30=80

180-80=100

Hope this helped :)

6 0
3 years ago
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