Ask question

Ask question

All categories

2 years ago

15

I need help on this math homework and I need the work please

1 answer:

Sav [38]2 years ago

5 0

For all of them do L×W and divide that by 2

You might be interested in

Which of the following catorgories of numbers describes the square root of 12

OlgaM077 [116]

Well, the square root of 12 is 3.464101615

6 0

3 years ago

Read 2 more answers

Mr. Dewalt suggested contacting a travel agent to see whether they could get a lower price. The agent found

Liono4ka [1.6K]

Finding a price that is 30% lower than $2075 is the same as finding a price that is 70% of $2075.

That means all we need to do is calculate what is 70% of $2075.

Convert 70% into decimal form which is 0.70.

Next, multiply $2075 by 0.70.

$2075*0.70 = $1452.50

The price the travel agent found was $1452.50

Note: If you don't know how to multiply by decimals you can multiply $2075 by 7 than divide the result by 10 (move the decimal point one place to the left).

7 0

2 years ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

3 years ago

Find the values of the variables and lengths of the sides of this kite.<br> Y-3, x+5, 2x+5, x+10

zzz [600]

Y=3
x=-5
x=-5/2
x=-10
.....................

4 0

3 years ago

Read 2 more answers

BRAINLIST HEHEH HELP PWEASEC

natka813 [3]

Answer:

A. The amount per text message.

B. 16x x y = 3.20

Step-by-step explanation:

A. the amount per text message doesn't change, only the amount of times you message does.

B. (below)

X- The amount of messages sent.

Y- The amount of months.

6 0

2 years ago