Answer:
Step-by-step explanation:
We can use the point-slope form given by:
Where <em>m</em> is the slope and (x₁, y₁) is a point.
So, we will substitute -2 for <em>m</em> and (5, 2) for (x₁, y₁). This gives us:
Simplify:
Distribute:
Add 2 to both sides. Hence, our equation is:
Percent increase/decrease is:
(Change/original amount)x100
(.25/2.35)x100= 10.6%
To find the z-score for a weight of 196 oz., use
A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
Y = 1.55x + 3.70
1.55 x 150 = 232.5
232.5 + 3.70 = 236.2
The answer is C 236.20 hope that helped.
