Answer:
6
Step-by-step explanation:
n(AUB) = n(A) + n(B) - n(AnB)
n(AUB) can have the minimum number of elements if n(AnB) has the maximum number of elements.
n(AnB) maximum = 3
so n(AUB) = 3+6-3 = 6
(2t-4)(3t+3)
2t(3t+3)-4(3t+3)
6t^2+6t-12t-12
6t^2-6t-12
Answer:
-28
Step-by-step explanation:
It is negative so:
52-24=28
-28
We have the following:
the formula for this case is the following:
replacing: