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3 years ago

Does anyone know how to do this??

Mathematics

1 answer:

insens350 [35]3 years ago

3 0

8

I assumed subtracting 29 from 21. And if you think about it, what else would you do so that’s what I did

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Please help DO NOT IGNORE DO NOT IGNORE

lisov135 [29]

Answer:

24.997 cm

Step-by-step explanation:

Find the diameter:

7(2) = 14 cm

Find the circumference:

C = $\pi d$

C = $\pi (14)$

C = 43.988

Divide the circumference by 4:

43.988/4 = 10.997

(This is the length of the curved side)

Add length to the other 2 sides:

7 + 7 + 10.997 = 24.997

3 0

4 years ago

Simplify<br><br>pls help me ASAP

Strike441 [17]

$\dfrac{\left(\dfrac{4}{3}ab^3\right)\left(\dfrac{6}{2}a^4\right)}{a^5}=\dfrac{\left(\dfrac{\not4^2}{\not3_1}\cdot\dfrac{\not6^2}{\not2_1}\right)(aa^4)(b^3)}{a^5}=\dfrac{4a^5b^3}{a^5}=\boxed{4b^3}$

3 0

4 years ago

Claire traveled 701 miles. She drove 80 miles every day. On the last day of her trip she only drove 61 miles. Write and solve an

mina [271]

Answer:

Claire traveled for 9 days.

Step-by-step explanation:

Given:

Total Distance traveled = 701 miles

Distance traveled each day = 80 miles

Distance traveled on last day = 61 miles

We need to find the number of days Claire traveled.

Solution:

Let the number of days Claire traveled be denoted by 'd'.

Now we can say that;

Total Distance traveled is equal to sum of Distance traveled each day multiplied by number of days and Distance traveled on last day.

framing in equation form we get;

$80d+61=701$

Now Subtracting both side by 61 using Subtraction Property of Equality we get;

$80d+61-61=701-61\\\\80d = 640$

Now Dividing both side by 80 we get;

$\frac{80d}{80}=\frac{640}{80}\\\\d=8$

Hence Claire traveled 80 miles in 8 days and 61 miles on last day making of total <u>9 days</u> of travel.

7 0

3 years ago

I need help please and thank you

Sedaia [141]

Answer:

20 hours

Step-by-step explanation:

3 0

3 years ago

Simplify the expression.

spayn [35]

Answer:

C. $\huge\frac{1}{3x {y}^{2} {z}^{4}}$

Step-by-step explanation:

$(9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = ( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } \\ \\ = \frac{1}{( {3}^{2} {x}^{2} {y}^{4} {z}^{8} )^{ \frac{1}{2} }} \\ \\ = \frac{1}{(3x {y}^{2} {z}^{4})^{2 \times \frac{1}{2} } } \\ \\ = \frac{1}{3x {y}^{2} {z}^{4}} \\ \\ \red{ \bold{ \therefore \: (9 {x}^{2} {y}^{4} {z}^{8} )^{ - \frac{1}{2} } = \frac{1}{3x {y}^{2} {z}^{4}} }}\\$

7 0

4 years ago