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marissa [1.9K]
3 years ago
12

Describe this translation Will give brainliest!

Mathematics
1 answer:
serious [3.7K]3 years ago
6 0

Answer:

6 units right and 4 units down :)

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The quotient of two numbers is -12. One of the numbers is −3. What is the other number?
umka21 [38]
The answer is -4 because -4 times -3 equals -12
6 0
3 years ago
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16. Find the point that partitions AB in the ratio 1:3 from A to B if A(-4,-7) and B (12,5).
Feliz [49]

Answer:

Step-by-step explanation:

8 0
2 years ago
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Solve the linear equation below for x. *<br> 3x + 4 = 8x – 9<br> A. 2.6 B. 1 C. 1.09 D. 2
Juli2301 [7.4K]
This answer is A, first you subtract 3x from both sides simplify 8x-9-3x to 5x-9, add 9 to both sides, simplify 4+9 to 13, divided both sides by 5 and you’ll get 2.6
6 0
3 years ago
What is the slope of the line that passes through ( 1, -19 ) and ( -2,-7
Lapatulllka [165]

Answer:

-4

Step-by-step explanation:

We can find the slope when given two points by using the following

m = (y2-y1)/(x2-x1)

  = (-7--19)/(-2 -1)

   = (-7+19)/(-2-1)

   = 12/-3

   =-4

3 0
3 years ago
For what values of x is log base 0.8 (x+4)&gt;log base 0.4 (x+4)<br>Thank you!
Radda [10]
We are seeking the solution of the inequality:

\displaystyle{ \log_{0.8}(x+4)\ \textgreater \ \log_{0.4}(x+4).


We recall that a log function f(x)=\log_b(x) is either increasing or decreasing:

i) it is increasing if b>1, 

ii) it is decreasing if 0<b<1.

Consider the functions \displaystyle{ \log_{0.8}(x) and \displaystyle{ \log_{0.4}(x).

The graphs of these functions both meet at x=1 (clearly), and after 1 they are both negative. So from 0 to 1 one of them is larger for all x, and from 1 to infinity the other is larger. (Being strictly decreasing, their graphs can only intersect once.)


We can check for a certain convenient point, for example x=0.8:

\displaystyle{ \log_{0.8}(0.8)=1 and

\displaystyle{ \log_{0.4}(0.8)=\log_{0.4}(0.4\cdot 2)=\log_{0.4}(0.4)+\log_{0.4}(\cdot 2)=1+\log_{0.4}(2).

Now, \displaystyle{ \log_{0.4}(2) is negative since we already explained that for x>1 both functions were negative. This means that 

\displaystyle{ \log_{0.8}(0.8)\ \textgreater \ \log_{0.4}(0.8), and since 0.8\in (0, 1), then this is the interval where \displaystyle{ \log_{0.8}(x)\ \textgreater \ \log_{0.4}(x).


So, now considering the functions \displaystyle{ \log_{0.8}(x+4) and \displaystyle{ \log_{0.4}(x+4), we see that 

x+4 must be in the interval (0,1), so we solve:

0<x+4<1, which yields -4<x<-3 after we subtract by 4.


Answer: (-4, -3). Attached is the graph generated using Desmos.

7 0
2 years ago
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