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3 years ago

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The equation gives the speed at impact, V metres per second, of an object dropped from a height of h metres. SHOW WORK From what

height must an object be dropped to impact the ground at a speed of 18.6 m/s?

1 answer:

devlian [24]3 years ago

4 0

Answer:

h = 17.65 m

Step-by-step explanation:

The given equation gives the speed at impact :

$v=\sqrt{2gh}$

h is height form where the object is dropped

Put v = 18.6 m/s in the above equation.

$h=\dfrac{v^2}{2g}\\\\h=\dfrac{(18.6)^2}{2\times 9.8}\\\\h=17.65\ m$

So, the object must be dropped from a height of 17.65 m.

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Apply the distributive property and then combine like terms to write an equivalent expression

Norma-Jean [14]

x + 7(x + 1)

7x + 7

x + 7x + 7

8x + 7

x + 7(x + 1) = 8x + 7

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3 years ago

Can someone help me with the questions in the picture?

OverLord2011 [107]

Answer:

$y = 8$

Step-by-step explanation:

Equation of the line that passes through (-2, 8) with a slope of 0, can be written in point-slope form, $y - y_1 = m(x - x_1)$ and also in slope-intercept form, $y = mx + b$ .

Using a point, (-2, 8) and the slope (m), 0, substitute x1 = -2, y1 = 8 and m = 0 in $y - y_1 = m(x - x_1)$ .

Thus:

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Rewrite in slope-intercept form

$y - 8 + 8 = 0 + 8$ (addition property of equality)

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3 years ago

A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen

Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

$A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}$

The restriction is that the perimeter have to be 12 ft at most:

$P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12$

We can express b in function of a as:

$2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a$

Then, the area become:

$A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2$

To maximize the area, we derive and equal to zero:

$\dfrac{dA}{da}=6-2\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right )a=0\\\\\\6-(1-\pi/4)a=0\\\\a=\dfrac{6}{(1+\pi/4)}\approx6/1.78\approx 3.36$

Then, b is:

$b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a\\\\\\b=6-0.393*3.36=6-1.32\\\\b=4.68$

3 0

3 years ago

Help me im not mentally gifted in math.

Oksi-84 [34.3K]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Choose the graphic representation of the quadratic function f(x) = x2 – 8x + 24.

larisa86 [58]

Refer the attached figure for the graphic representation of the given quadratic equation.

<u>Step-by-step explanation:</u>

Given expression:

$f(x)=x^{2}-8 x+24$

To find:

The graphic representation of the given quadratic function

For solution, plot the graph to the given quadratic equation.

The standard form of the equation is

$y=a x^{2}+b x+c$

When comparing with given quadratic equation,

a = 1, b = - 8, c = 24

Axis of symmetry is $x=\frac{-b}{2 a}$

By applying the values, the axis of symmetry of given equation is

$x=\frac{-(-8)}{2(1)}=4$

The vertex form of quadratic equation is $f(x)=a(x-h)^{2}+k$

Where, (h,k) are the vertex.

Convert the quadratic equation into vertex form.

By completing the square,

$f(x)=x^{2}-8 x+24$

$f(x)=\left(x^{2}-2(4) x+4^{2}\right)-4^{2}+24$

$f(x)=(x-4)^{2}+8$

On comparison,

(h , k) = (4 , 8)

Now, plot the equation with vertex (4,8) [refer attached figure].

4 0

3 years ago