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2 years ago

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The equation gives the speed at impact, V metres per second, of an object dropped from a height of h metres. SHOW WORK From what

height must an object be dropped to impact the ground at a speed of 18.6 m/s?

1 answer:

devlian [24]2 years ago

4 0

Answer:

h = 17.65 m

Step-by-step explanation:

The given equation gives the speed at impact :

$v=\sqrt{2gh}$

h is height form where the object is dropped

Put v = 18.6 m/s in the above equation.

$h=\dfrac{v^2}{2g}\\\\h=\dfrac{(18.6)^2}{2\times 9.8}\\\\h=17.65\ m$

So, the object must be dropped from a height of 17.65 m.

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Jennifer earns $17.35 per hour at her job. She works 6 hours per day, 5 days per week. What is Jennifer’s gross income for a 2 w

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Answer:

She makes $1041 in 2 weeks

Step-by-step explanation:

First, we can work on finding how much she makes in a day. To find the daily income, we need to multiply 17.35 by 6 since she works 6 hours a day.

17.35x6=104.1

She makes $104.10 a day. Now we multiply by 5 since she works 5 days a week

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2 years ago

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

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inn [45]

Answer:

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Step-by-step explanation:

We are given the equation $\displaystyle \large{y=12x}$ . To find y-value when or at x = 3, simply substitute x = 3 in which gives us $\displaystyle \large{y=12(3)}$ then evaluate the value as we obtain the y-value or final answer to the question:

$\displaystyle \large{\boxed{y=36}}$

If you have any questions about this question or for clarification, do not hesitate to ask in comment!

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