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Len [333]
3 years ago
11

-4y minus 3 plus 3y equals 8 minus 2y minus 15

Mathematics
1 answer:
kenny6666 [7]3 years ago
5 0
Y= -4
i’ll attach an image showing work

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Evaluate 104+(-46)-(-32)
Dima020 [189]

104 + (-46) - (-32) is equal to 90

7 0
3 years ago
Read 2 more answers
the length of a rectangle is 5 more than twice its width. its perimeter is 88 feet. find its dimensions
podryga [215]
Length = x; width = y
2x+2y=88
x=2y+5
4y+10+2y=88
6y=78
y=13 feet
x=26+5
x=31 feet
3 0
3 years ago
Let f(x) = -­2x ­- 7 and g(x) = ­-4x + 3. Find (f o g)(-­5)
musickatia [10]
The answer is:  [A]:  " -53 " .
_______________________________________________________
Explanation:
_______________________________________________________
Given:  

" Let f(x) = -­2x ­−<span> 7 and g(x) = ­-4x + 3.  Find (f o g)(-­5) " ;
_______________________________________________
First, find g(-5) .   g(x) = -4x + 3.  

g(-5) = -4*(-5)  + 3 = 20 + 3 = 23 ;
_______________________________________________
Now find f (g(-5) to get the answer; that is f(23); 
_______________________________________________
  Find f(23).  f(x) = -2x </span>− 7 .  
 
  f(23) = (-2*23) − 7 = -46 <span>− </span>7 = -53 ; which is "Answer choice: [A]" .
_______________________________________________
3 0
3 years ago
Find the modulus of -2 - 6i.<br><br> 40<br> -40<br> 6.3<br> -6.3
olga2289 [7]
The modulus of complex number can be computed with this equation:
|z|=sqrt(Re(z)^2+Im(z)^2)
z = -2-6i
Re(z)=-2, so Re(z)^2=4
Im(z)=-6, so Im(z)^2=36
|z|=sqrt(36+4)=sqrt(40)=6.3
6 0
3 years ago
How much greater is the area of a square with a side length of 9 inches than the area of a circle with a radius of 3 inches?
fredd [130]
The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx  28.27 sq in.

Subtract:  81 sq in - 28.27 sq in = approx. 52.73 sq in.

The difference is 52.73 sq in; the square is larger, the circle smaller.
7 0
3 years ago
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