Write the ratio as a fraction in simplest form with whole numbers in the numerator and denominator 16 cm to 20 cm
2 answers:
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Answer:
We need to find which expressions are equivalent to ,
or neither.
: We extract the greatest common factor which is 6. Remember, when we extract a GCM, we divide each term by it.
Therefore, this expression is equivalent to neither of the given expressions.
: We just need to apply the distributive property.
Therefore, this expression is equivalen to .
We use the same process to the other expressions.
, equivalent to neither.
slope is -1
we have a point as (-4,3)
we can use slope intercept form of line
we can plug m=-1
now, we can plug point (-4,3)
x=-4 and y=3 and then we can find b
now, we can plug back
and we get
............Answer
Answer:
a) 0.0951
b) 0.8098
c) Between $24.75 and $27.25.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
(a)
What is the likelihood the sample mean is at least $27.00?
This is 1 subtracted by the pvalue of Z when X = 27. So
By the Central Limit Theorem
has a pvalue of 0.9049
1 - 0.9049 = 0.0951
(b)
What is the likelihood the sample mean is greater than $25.00 but less than $27.00?
This is the pvalue of Z when X = 27 subtracted by the pvalue of Z when X = 25. So
X = 27
has a pvalue of 0.9049
X = 25
has a pvalue of 0.0951
0.9049 - 0.0951 = 0.8098
c)Within what limits will 90 percent of the sample means occur?
50 - 90/2 = 5
50 + 90/2 = 95
Between the 5th and the 95th percentile.
5th percentile
X when Z has a pvalue of 0.05. So X when Z = -1.645
95th percentile
X when Z has a pvalue of 0.95. So X when Z = 1.645
Between $24.75 and $27.25.