Answer:
lies between 0 and 1.
Step-by-step explanation:
We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:
, 
Which is now developed mathematically to deduce a useful expression to find integers:
1) Given
2) 
Modulative property
3) 
Existence of Multiplicative inverse/Definition of division.
4) ![(n\cdot b)\cdot b^{-1} < a\cdot b^{-1}< [(n+1)\cdot b] \cdot b^{-1}](https://tex.z-dn.net/?f=%28n%5Ccdot%20b%29%5Ccdot%20b%5E%7B-1%7D%20%3C%20a%5Ccdot%20b%5E%7B-1%7D%3C%20%5B%28n%2B1%29%5Ccdot%20b%5D%20%5Ccdot%20b%5E%7B-1%7D)
Commutative, Associative and Distributive properties.
5) 
Compatibility with Multiplication/Existence of Multiplicative Inverse/Modulative Property/Result.
If we know that 
and 
, the following inequation is formed:
It is quite evident to conclude that lies between 0 and 1.
We have to simplify
sec(θ) sin(θ) cot(θ)
Now first of all let's simplify these separately , using reciprocal identities.
Sec(θ) = 1/cos(θ)
Sin(θ) is already simplified
Cot(θ)= cos(θ) / sin(θ) ,
Let's plug these values in the expression
sec(θ) sin(θ) cot(θ)
= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )
= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
sin cancels out with sin and cos cancels out with cos
So , answer comes out to be
=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
= 1
You use rise over run. So you first count the rise( how many upwards is the point) then count the run( how many to the right or left is the point)
C, B, G common vortex ( B) and common side (C, G)
Y = yo + Vot - (gt^2)/2
0 = 0 + 31t - 4.9 t^2
0 = -4.9 t^2 + 31t
Answer: option A.
