Your answer would be 1.13 repeating or no solution.
Answer:
Step-by-step explanation:
<u>Assume a solution</u>
Assume that 60 is the length. The width is then 1/4 less, or 60 -60/4 = 45.
The diagonal of this rectangle is found using the Pythagorean theorem:
d = √(60² +45²) = √5625 = 75
<u>Make the adjustment</u>
This is a factor of 75/40 larger than the actual diagonal, so the actual dimensions must be 40/75 = 8/15 times those we assumed.
length = (8/15)×60 = 32
width = (8/15)×45 = 24
The length and width of the rectangle are 32 and 24, respectively.
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<em>Comment on this solution method</em>
This method is suitable for problems where variables are linearly related. If we were concerned with the area, for example, instead of the diagonal, we would have to adjust the linear dimensions by the <em>square root</em> of the ratio of desired area to "false" area.
Hi there!
Th' Eqn. is :-
4 (x - 3) = 2 (3x + 1)
=> 4x - 12 = 2 (3x + 1)
=> 4x - 12 = 6x + 2
Combine th' like terms :-
=> 4x - 6x = 2 + 12
=> - 2x = 14
=> x =

=> x = - 7
Hence, The required answer is : x = - 7
~ Hope it helps!
Answer:
a) 6 mins
b) 70km/h
c) t= 45
Step-by-step explanation:
a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km
Duration
= 16 -10
= 6 minutes
b) Average speed
= total distance ÷ total time
Total time
= 24min
= (24÷60) hr
= 0.4 h
Average speed
= 28 ÷0.4
= 70 km/h
c) Average speed= total distance/ total time
Average speed
= 80km/h
= (80÷60) km/min
= 1⅓ km/min
1⅓= 28 ÷(t -24)
<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>
(t -24)= 28
t - 32= 28
t= 32 +28
t= 60
t= 
t= 45
*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.
Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)
<span>The three consecutive even integers are 92, 94, and 96.
~Jurgen</span>