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2 years ago

Help me and I’ll give you Brainliest and if u don’t know don’t answer

Mathematics

2 answers:

vagabundo [1.1K]2 years ago

5 0

Answer:

2 in. × 25 in. [Choice 2]
5 in. × 10 in. [Choice 4]
1 in. × 50 in. [Choice 6]

inysia [295]2 years ago

3 0

1 4 7 I think
I don’t know for sure though

You might be interested in

Travis takes out a loan from his bank for $3,500. At the end of the year, Travis will need to pay the loan back to his bank alon

Reil [10]

Answer:

$3,787

Step-by-step explanation:

frist find the amount of intrest

3,500 X 0.082 X 1 = 287

next add the oragial amount to the amount of intrest

3,500 + 287 = 3,787

6 0

2 years ago

The other side is 10 yds

Vesnalui [34]

The correct answer is 900yds.

6 0

2 years ago

PLEASE HELP GUYS i am struggling so much, two questions

ankoles [38]

Answer: the equation of the standard parabola

1) $(y-6)^2 = 4 (x-1)$

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

Explanation

Parabola:-

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

The locus of P such that $\frac{SP}{PM} = constant$
The fixed point 'S' is called the Focus.
The fixed line'l 'is called the directrix of the conic
The constant ratio is known as the eccentricity, denoted by 'e'
If e=1 , the conic is called a parabola

1) Step 1 :-

Given the focus S = (2,6) and directrix is x=0

we know that $\frac{SP}{PM}=1$

now cross multiplication , we get

$SP = PM$

squaring on both sides,we get

$SP^{2} = PM^2$

step 2:-

now using distance formula is

$\sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)$

Given S =(2,6) and P(x,y) be any point on parabola

$SP^2 = (x-2)^2+(y-6)^2$ ........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

$\frac{ax_{1}+by_{1}+c }{\sqrt{a^2+b^2} }$

Given the directrix is x =0 and P(x,y) be any point on parabola

$PM^2 = \frac{x^2}{\sqrt{1}^2 }$ ......(2)

equating equation(1) and equation (2), on simplification

we get $(x-2)^2+(y-6)^2 = x^2$ .....(3)

apply $(a-b)^2 = a^2+ b^2+2 ab$

now the equation (3) is

$(y-6)^2 = 4 x-4$

now the standard form of parabola is

$(y-k)^2 = 4 a(x-h)$

Final answer:-

$(y-6)^2 = 4 (x-1)$

2) Explanation:-

step 1:

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

$(x-h)^2 = 4 a (y-k)$

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of $AS = \sqrt{(-5-(-5)^2+(2-6)^2}$

on simplification we get a =4

Final answer :-

the vertex (h,k) = (-5,2) and a=4

$(x-h)^2 = 4 a (y-k)$

The standard parabola is $(x+5)^2 = 16 (y-2)$

5 0

3 years ago

Awnser choices a-360 b- 9 c-10 d-180

cluponka [151]

Answer:

C- 10

Step-by-step explanation:

$2x + 160 = 180 \\ 2x = 180 - 160 \\ 2x = 20 \\ x = 20 \div 2 \\ x = 10$

7 0

2 years ago

Read 2 more answers

A convex mirror in an amusement park has a radius of curvature of 3. 00 m. A man stands in front of the mirror so that his image

densk [106]

The convex mirror in the park is an illustration of lens magnification

The man must focus his eyes at 4.50 meters to see his image

<h3>How to determine the object distance?</h3>

The given parameter is:

Radius of curvature, r = 3.00 m

The magnification (m) of the mirror is 1/2, because the image (v) is half as tall as the actual height (u).

So, we have:

m = u/v

So, we have:

u/v = 1/2

Make v the subject

v = 2u

The focal length is calculated as:

1/f = 1/u + 1/v

The focal length is calculated as:

f = r/2

f = 3/2

Substitute f = 3/2 in 1/f = 1/u + 1/v

2/3 = 1/u + 1/v

Substitute v = 2u in 2/3 = 1/u + 1/v

2/3 = 1/u + 1/2u

Take the LCM

2/3 = (2 + 1)/2u

This gives

2/3 = 3/2u

Take the inverse of both sides

3/2 = 2u/3

Cross multiply

2u = 3 * 3

4u = 9

Divide both sides by 4

u = 9/4

This gives

u = 2.25

Recall that:

v = 2u

So,we have:

v = 2 * 2.25

v = 4.50

Hence, the man must focus his eyes at 4.50 meters to see his image