Answer:
Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4
Step-by-step explanation:
I attached the graph of the function.
Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0
When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2)) 
Hey!To solve this problem, we need to set up two equations and use the system of equations to solve.
Let x be the first number.
Let y be the second number.
(x + y) ÷ 2 = 34
x = 3y
Now, we can use substitution to solve.
(3y + y) ÷ 2 = 34
4y ÷ 2 = 34
2y = 34
y = 17
Now, you plug the value of y in the equation to solve for x.
x = 3*17
x = 51
hope this helps!!
Get them to have a common denominator so you can add them
(1/3)×2= 2/6 and (1/2)×3= 3/6
Add them together
(2/6)+ (3/6)= 5/6
So 5/6 of the class planted either marigolds or tulips and 1/6 of the class planted neither
It would not have an effect on the gross income. Hope this helps
for the red it is 5out of 15 or 3/5
and for the blue it is 4/15
and if it wants it together it is 9/15 or 3/5
hope this helps
