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3 years ago

What is equivalent to 4 5/3

Mathematics

1 answer:

storchak [24]3 years ago

4 0

Answer: 17/3

Step-by-step explanation:

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Solve the problem.

choli [55]

Answer:

6 $\frac{3}{100}$

Step-by-step explanation:

$603 dollars ÷ 100 shoppers = $6.03 per shopper, or 6 $\frac{3}{100}$ as a mixed number

4 0

3 years ago

The Japanese 5 yen coin has a hole in the middle. If the diameter of the coin is 22 mm and the diameter of the hole is 5 mm, how

Yanka [14]

Answer:

4.4mm

Step-by-step explanation:

Circumference of circle

2 Pi r

Diameter of coin = 22mm

Therefore the radius = 11mm

Therfroe the outer edge (circumference)

= 2 Pi r

= 2 x Pi x 11

=69.11mm

For the inner edge

Diameter = 5

Radius = 2.5

Therefroe inner edge (circumference)

= 2 Pi r

= 2 x Pi x 2.5

= 15.7mm

The difference is

69.11 - 15.7

=4.4mm

7 0

3 years ago

The leaning tower of Pisa currently "leans" at a 4 degree angle and has a vertical height of 55.86 meters. How tall was the lean

Marizza181 [45]

Answer:

56 meters.

Step-by-step explanation:

Please find the attachment.

Let the leaning tower's be h meters tall, when it was originally built.

We can see from our attachment that the side with length 55.86 meters is hypotenuse and h is adjacent side for 4 degree angle.

Since we know that cosine relates the adjacent and hypotenuse of a right triangle.

$\text{Cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}$

Upon substituting our given values we will get,

$\text{Cos (4)}=\frac{55.86}{h}$

$h=\frac{55.86}{\text{Cos (4)}}$

$h=\frac{55.86}{0.99756405026}$

$h=55.996\approx 56$

Therefore, the leaning tower was approximately 56 meters, when it was originally built.

6 0

3 years ago

HELPPPPP ASAPPPP

KATRIN_1 [288]

Answer:

The maximum height of the volleyball is 12.25 feet.

Step-by-step explanation:

The height of the volleyball, h(t), is modeled by this equation, where t represents the time, in seconds, after that ball was set :

$h(t)=-16t^2+20t+6$ ....(1)

The volleyball reaches its maximum height after 0.625 seconds.

For maximum height,

Put $\dfrac{dh}{dt}=0$

Now put t = 0.625 in equation (1)

$h(t)=-16(0.625)^2+20(0.625)+6\\\\h(t)=12.25\ \text{feet}$

So, the maximum height of the volleyball is 12.25 feet.

5 0

3 years ago

What is the quotient of a number a and a number c

Hatshy [7]

Quotient is simply the result of dividing.

7 0

3 years ago