Answer:
The expected value of the winnings for a single-ticket purchase is -$1.0016.
Step-by-step explanation:
The total number of tickets sold is, <em>N</em> = 1250.
Cost of one ticket is, $4.
Let <em>X</em> = amount of prize.
The prize distribution is as follows:
1 Grand price = $3000
1 Second prize = $450
10 Third prize = $25
The expected value <em>X</em> can be computed using the formula:

Compute the probability distribution of <em>X</em> as follows:
Prize Amount (X) P (X) x · P (X)
1 Grand prize $3000

1 Second prize $450

10 Third prize $25

No prize -$4

TOTAL 1.0000 -1.0016
Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.
yes because it has equal sides
Answer:
1/2.
Step-by-step explanation:
10m = 5n
m = 5n/10
m = n/2
m/n = n/2 * 1/n
m/n = 1/2.
From the explanation below,
a= -10 and b= -4
19 x 3 = 57
57 - 9 = 48
Your answer is 19.