Answer is <span>C) 8 hours
hope it helps</span>
15 I believe.. I could be wrong bc idk if youre adding the A's to the ratio or starting at 0
Answer:
21,600
Step-by-step explanation:
If in the coding system being used there are 6 vowels (A, E, I , O, U and Y)
Number of Consonants =26-6 =20
- First entry must be a consonant, therefore the first entry can be chosen in 20 ways.
- The second entry must be an integer 1 through 9, therefore the second entry can be chosen in 9 ways.
- The third entry must be one of the six vowels, therefore the third entry can be chosen in 6 ways.
- The last entry must be a consonant, therefore the last entry can be chosen in 20 ways.
Therefore:
Number of different possible ciphers =20*9*6*20
=21600
M=-1
I think I'm sorry if it isn't right
Answer:
So you have a box, with weight Wb and you have a right force of 6N and a left force of Fl
With sum of forces you get that to maintain equilibrium the force Fl must be 6 therfore to maintain moving right the left force must be 5N
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