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Elis [28]
2 years ago
7

What is the equation of a circle with center (2, 3) that passes through the point (5, 3)​

Mathematics
1 answer:
alexdok [17]2 years ago
6 0

Answer:

(x−2)^2+(y+1)^2=26

Step-by-step explanation:

https://socratic.org/answers/456712

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Subtract the following complex numbers:<br> (3 +31) - (13+15)
vova2212 [387]

Answer:

33-28=5

Step-by-step explanation:

hope this helps

6 0
2 years ago
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What shape will result when you make a vertical cross section through the picture below?
Goryan [66]

Answer:

rectangle

Step-by-step explanation:

3 0
2 years ago
What is the solution for x in the equation? 16x − 4 + 5x = -67
Luden [163]

Answer:

x = -3

Step-by-step explanation:

16x − 4 + 5x = -67

Combine like terms

21x -4 = -67

Add 4 to each side

21x-4+4 = -67+4

21x = -63

Divide each side by 21

21x/21 = -63/21

x = -3

3 0
2 years ago
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Factor the following expression: 12x+4-16x
zepelin [54]

Answer:

12x+4-16x = 0

-4x + 4 = 0

-4x = 0-4

x = -4/-4

x= 1

7 0
3 years ago
Find the smallest positive integer solution to the following system of congruences: x = 0 (mod 5) x = 8 (mod 11) The solution is
igomit [66]

Answer:

The smallest positive integer solution to the given system of congruences is 30.

Step-by-step explanation:

The given system of congruences is

x=0(mod5)

x=8(mod11)

where, m and n are positive integers.

It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as

x=5m

x=11n+8

5m\cong 11n+8

Now, we can say that m>n because m and n are positive integers.

For n=1,

5m=11(1)+8=19

5m=19

19 is not divisible by 5 so m is not an integer for n=1.

For n=2,

5m=11(2)+8

5m=30

m=6

The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

x=5(6)=30

Therefore the smallest positive integer solution to the given system of congruences is 30.

8 0
3 years ago
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