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USPshnik [31]
3 years ago
11

6x:64=18:32pls helo me am stuck ​

Mathematics
1 answer:
zalisa [80]3 years ago
4 0

Answer:

384

Step-by-step explanation:

I think its 384 I say I think

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If f(x) = 4x + 2, what is the value of f(3)? <br><br> O 8<br> O 14<br> O 45<br> O 66
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14

Step-by-step explanation:

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Reduce the fraction to lowest terms m^2/m^2-n^2
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Answer:

\boxed{\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}}

Step-by-step explanation:

Factor \bold{m^2-n^2}

\bold{\left(m+n\right)\left(m-n\right)}

Rewrite Equation

\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}

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Write an expression showing 5 less than the number K
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The square on the right is a scaled copy of the square on the left. Identify the scale factor. Express your answer in simplest f
zhannawk [14.2K]

Answer:

x = 21/8

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A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What
vladimir2022 [97]

Answer:

The perimeter of the triangle is 12\ units

Step-by-step explanation:

Let

A(-3,1),B(1,1),C(1,-2)

we know that

The perimeter of triangle is equal to

P=AB+BC+AC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

A(-3,1),B(1,1)

substitute in the formula

AB=\sqrt{(1-1)^{2}+(1+3)^{2}}

AB=\sqrt{(0)^{2}+(4)^{2}}

AB=4\ units

step 2

Find the distance BC

B(1,1),C(1,-2)

substitute in the formula

BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}

BC=\sqrt{(-3)^{2}+(0)^{2}}

BC=3\ units

step 3

Find the distance AC

A(-3,1),C(1,-2)

substitute in the formula

AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}

AC=\sqrt{(-3)^{2}+(4)^{2}}

AC=5\ units

step 4

Find the perimeter

P=AB+BC+AC

substitute the values

P=4+3+5=12\ units

6 0
3 years ago
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