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fomenos
3 years ago
10

Is this the correct solution? 6x ≥ 50 --> x ≥ 8 1/3 Yes or No

Mathematics
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

Yes this would be correct!!!!

Step-by-step explanation:

You might be interested in
Find x.<br><br>How would you solve this?​
Murrr4er [49]

Answer:

x = 100°

Step-by-step explanation:

The measure of a chord- chord angle is half the sum of the arcs intercepted by the angle and its vertical angle, that is

x = \frac{1}{2} (71 + 129)° = 0.5 × 200° = 100°

7 0
3 years ago
15/16<br> How do you solve it?
Sever21 [200]

Answer:

0.9375

divide the numerator by the denominator

ex. 15 divided by 16

Step-by-step explanation:

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(
SSSSS [86.1K]

Answer:

We conclude that:

\sqrt{\left(-81\right)x^2}=9ix

Step-by-step explanation:

Given the radical expression

\sqrt{\left(-81\right)x^2}

simplifying the expression

\sqrt{\left(-81\right)x^2}

Remove parentheses:  (-a) = -a

\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}

Apply radical rule:   \sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0

                 =\sqrt{-1}\sqrt{81x^2}

Apply imaginary number rule:  \sqrt{-1}=i

                 =i\sqrt{81x^2}

Apply radical rule:   \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

                  =\sqrt{81}i\sqrt{x^2}

                  =9i\sqrt{x^2}

Apply radical rule:  \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

                  =9ix

Therefore, we conclude that:

\sqrt{\left(-81\right)x^2}=9ix

7 0
3 years ago
Does somebody knows how to do this?
MrMuchimi

Answer:

Area of the triangle = 6x3/2=18/2=9cm²

now find semicircle then add

area of the semicircle= πr²/2=π6²/2=36π/2=18π

now add and you get

Area of the region = (18π+9)cm²

Step-by-step explanation:

5 0
3 years ago
Pleaseee help me asap
pychu [463]

Answer:

k = 13.5

Step-by-step explanation:

Setup proportion and solve for k:

\frac{k}{9} =\frac{4.5}{3} \\3k = 40.5\\k=13.5

8 0
3 years ago
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