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kupik [55]
3 years ago
15

If Sn=2^n-1what's the expression ofSn-1?​

Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0

Answer:

S(n-1)=2^{n-2}

Step-by-step explanation:

Given that,

The value of S_n=2^{n-1}

We need to find an expression for S(n-1). To find it, put the value of n as (n-1). So,

S_{n-1}=2^{n-1-1}\\\\=2^{n-2}

Hence, the value of S(n-1) is equal to 2^{n-2}.

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