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2 years ago

If Sn=2^n-1what's the expression ofSn-1?

Mathematics

1 answer:

Naya [18.7K]2 years ago

4 0

Answer:

$S(n-1)=2^{n-2}$

Step-by-step explanation:

Given that,

The value of $S_n=2^{n-1}$

We need to find an expression for $S(n-1)$ . To find it, put the value of n as (n-1). So,

$S_{n-1}=2^{n-1-1}\\\\=2^{n-2}$

Hence, the value of S(n-1) is equal to $2^{n-2}$ .

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Answer:

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Step-by-step explanation:

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telo118 [61]

Answer:

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Step-by-step explanation:

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2 years ago

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mart [117]

Answer:

Answer:the answer is zero 

Answer:the answer is zero Step-by-step explanation:

Answer:the answer is zero Step-by-step explanation:when we add -42 and -54 the answer we get is -96. -96and +96 cut each other and then the answer is zero 

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2 years ago

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Lubov Fominskaja [6]

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If Sn=2^n-1what's the expression ofSn-1?​

If Sn=2^n-1what's the expression ofSn-1?