we are given that
angle(ACF)=90
angle(ACB)=61
sum of all angles along any line is 180
so, we get
angle(ACF)+angle(ACD)=180
we can plug value
90+angle(ACD)=180
angle(ACD)=90
now, we can use formula
angle(ACD)=angle(ACB)+angle(BCD)
now, we can plug values
and we get
90=61+angle(BCD)
90-61=61-61+angle(BCD)
angle(BCD)=29................Answer
I would go with B i had this question on my test and i got it correct
Answer:
the answer is on photomath
I disagree. The first one is false. No exponent rules apply if the bases AND the exponents are different.
The second one is true. Bases are the sane so you add exponents. You get 3 to the -5 power. Written with positive exponents it’s 1/3 to the 5.
Take 0.53 and 0.7 by 100 to make them percents. 0.53 times 100 is 53% and 0.7 time 100 is 70%. so 0.7>0.53
